ios - 如何获取这段 Swift 代码以接收 PHP 脚本的返回值？

Question

我正在运行一个简短的 Swift 脚本来将一些变量发布到一个 PHP 脚本中，然后读取返回值:

  let myUrl = URL(string: "http://www.quasisquest.uk/KeepScore/createCommunity.php");

    var request = URLRequest(url:myUrl!);
    request.httpMethod = "POST";

    let postString = "communityname=\(communityName!)&code=\(communityCode)&email=\(myEmail!)";

    request.httpBody = postString.data(using: String.Encoding.utf8);

    let task = URLSession.shared.dataTask(with: request) { (data: Data?, response: URLResponse?, error: Error?) in

    let json = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]

           print (json["code"]);
           print (json["email"]);
           print (json["communityname"]);


        }
        task.resume()
    }

在我下面的 PHP 代码中，我只想接收值，然后将它们返回到一个数组中:

<?php

ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);


require("Conn.php");
require("MySQLDao.php");

$email = htmlentities($_POST["email"]);
$code = htmlentities($_POST["code"]);
$communityname = htmlentities($_POST["communityname"]);

$returnValue = array();

$returnValue["code"] = $code;
$returnValue["email"] = $email;
$returnValue["communityname"] = $communityname;

echo json_encode($returnValue);

?>

我知道我在 Swift 代码的末尾做错了什么，但我不知道是什么。

我在 let task 行收到此错误:

从类型“(Data?, URLResponse?, Error?) throws -> ()”到非抛出函数类型“(Data?, URLResponse?, Error?) -> Void 的无效转换'

Answer 1

也许您没有包含所有代码，但是...您是在调用 task.resume() 吗？

试试这个:

let myUrl = URL(string: "http://www.quasisquest.uk/KeepScore/createCommunity.php");
var request = URLRequest(url:myUrl!);
request.httpMethod = "POST";

let postString = "communityname=\(communityName!)&code=\(communityCode)&email=\(myEmail!)";
request.httpBody = postString.data(using: String.Encoding.utf8);

let task = URLSession.shared.dataTask(with: request) { (data, response, error) in
    if let json = try! JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject] {
        print (json["code"]);
        print (json["email"]);
        print (json["communityname"]);
    }
}

task.resume()