我看过很多关于遍历字典的帖子,但在我看来,它们与我在这里想要实现的目标不同且更简单。我有以下数组:
pt1.array = [0:[pt2.point],
1:[pt8.point, pt12.point, pt4.point],
2:[pt20.point, pt14.point, pt3.point],
3:[pt7.point, pt8.point, pt9.point]]
pt2.array = [0:[pt5.point],
1:[pt8.point, pt11.point, pt1.point],
2:[pt10.point, pt9.point, pt3.point],
3:[pt6.point, pt1.point, pt4.point]]
pt3.array = [0:[pt13.point],
1:[pt1.point, pt15.point, pt7.point],
2:[pt19.point, pt14.point, pt2.point],
3:[pt10.point, pt11.point, pt12.point]]
pt4.array = [0:[pt8.point],
1:[pt9.point, pt11.point, pt13.point],
2:[pt14.point, pt15.point, pt6.point],
3:[pt3.point, pt2.point, pt1.point]]
pt5.array = [0:[pt18.point],
1:[pt8.point, pt6.point, pt1.point],
2:[pt3.point, pt17.point, pt4.point],
3:[pt16.point, pt15.point, pt14.point]]
allPoints = [pt1, pt2, pt3, pt4, pt5]
我如何迭代以从 中的所有
数组?Int
-[CGPoint]
字典中删除 pt3.point
这是一个 CGPoint >allPoints
我尝试了以下方法:
for pt in allPoints {
for ptArrIndex in pt.arrays {
for (key, value) in ptArrIndex {
//remove point from dict here
}
}
}
但是我得到了错误:
Type '(key: Int, value:[CGPoint])' (aka'(key: Int, value: Array<CGPoint>)') does not conform to protocol 'Sequence'
在线:
for (key, value) in ptArrIndex {
编辑
创建每个点的结构如下:
struct Point {
var point: CGPoint
var arrays: [Int: [CGPoint]]
}
更新问题
根据 Rob Napier 的建议,我更新了问题:
我有一个结构如下:
struct Location {
var point: CGPoint
var changedLoc: [Int: [CGPoint]]
}
其中 point
表示 Location
的 CGPoint
而 changedLoc
表示所有可能的 CGPoints 组Location
可以更改为。我是随机计算的。
我有以下位置
var location1 = Location(point: initialBallPosition, changedLoc: [0: [CGPoint(x: 421.0, y: 43.0), CGPoint(x: 202.0, y: 69.0)], 1: [CGPoint(x: 121.0, y: 198.0)]])
var location2 = Location(point: initialBallPosition, changedLoc: [0: [CGPoint(x: 421.0, y: 43.0), CGPoint(x: 123.0, y: 254.0)], 1: [CGPoint(x: 90.0, y: 104.0)]])
var allLocations = [location1, location2]
从 allLocations
我怎样才能删除点 CGPoint(x: 421.0, y: 43.0)
这在 location1
和 location2
changedLoc
?
最佳答案
func locationsRemoving(changedLoc removePoint: CGPoint, from locations: [Location]) -> [Location] {
return locations.map { location in
var changedLoc: [Int: [CGPoint]] = [:]
for (key, values) in location.changedLoc {
changedLoc[key] = values.filter{ $0 != removePoint }
}
return Location(point: location.point, changedLoc: changedLoc)
}
}
let removePoint = CGPoint(x: 421.0, y: 43.0)
print(allLocations)
print(locationsRemoving(changedLoc: removePoint, from: allLocations))
关于swift - 如何从字典中删除某个 CGPoint,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42120076/