ios - SwiftyJSON 转换为多个字符串数组

Question

给定以下示例 JSON

{
    "filters": [ 
      { "name" : "First Type",
        "types" : ["md", "b", "pb"]},
      { "name" : "Second Type",
        "types" : ["pt", "ft", "t"]},
      { "name" : "Third Type",
        "types" : ["c", "r", "s", "f"]
      }
    ],
    "jobs": [
        { "title":"f",
          "description" : "descrip text",
          "criteria":[ "md", "ft", "s" ],
          "img" : "www1"
        },
        { "title":"boa",
          "description" : "a description",
          "criteria":[ "b", "pb", "f", "ft" ],
          "img" : "www2"
        },
        { "title":"BK",
          "description" : "something here",
          "criteria":[ "md", "pt", "ft", "b", "s" ],
          "img" : "www3"
        }
    ]
 }

(使用 Alamofire 创建响应) 让 responseJSON : JSON = JSON(response.result.value!)

1) 我试图将它们转换成两个字符串数组。一个数组:let filter = [String : [String]] 和另一个数组用于作业。我该怎么做？ (又名授人以鱼)以下是一些示例代码片段，但没有一个能正常工作。

  let filterCategories = responseJSON["filters"].arrayValue.map({
          $0["name"].stringValue
  })

和

for (key,subJson):(String, JSON) in responseJSON["filters"] {
    let object : filterObject = filterObject(category: key, list: subJson.arrayValue.map({ $0.stringValue }))

  }

2) 我如何学习如何正确使用它？ (又名授人以渔)我一直在阅读文档 ( https://github.com/SwiftyJSON/SwiftyJSON )，但我很难理解它。我猜最终答案将使用 .map、.stringValue 和 .arrayValue。最终，虽然我试图避免大量不必要或难以管理的代码。

Answer 1

Swift 4 提供开箱即用的 JSON 解析支持 - 可能从类似 Ultimate Guide to JSON Parsing with Swift 4 的内容开始

根据你的可用结构，我扔进了一个 Playground 并使用了......

// I was loading the JSON from a file within the Playground's Resource folder
// But basically, you want to end up with a reference to Data
let filePath = Bundle.main.path(forResource:"Source", ofType: "json")
let data = FileManager.default.contents(atPath: filePath!)

struct Filter: Codable {
    let name: String;
    let types: [String];
}

struct Job: Codable {
    let title: String;
    let description: String;
    let criteria: [String];
    let img: String;
}

struct Stuff: Codable {
    let filters: [Filter];
    let jobs: [Job];
}

let decoder = JSONDecoder();
let stuff = try! decoder.decode(Stuff.self, from: data!)

print("Filter:")
for filter in stuff.filters {
    print(filter.name)
    for type in filter.types {
        print(" - \(type)")
    }
}
print("Jobs:")
for job in stuff.jobs {
    print(job.title)
    print(job.description)
    print(job.img)
    for type in job.criteria {
        print(" - \(type)")
    }
}

解析结果