最近想根据indexPaths删除单元格,所以函数的入参是[IndexPath]
类型,需要根据把[IndexPath]拆分成几个数组indexPath.section
,有什么简单的方法吗?
例如
indexPaths =
[IndexPath(row: 0, section: 1),
IndexPath(row: 1, section: 1),
IndexPath(row: 2, section: 1),
IndexPath(row: 2, section: 0)]
想把这个转换成
indexPath1 =
[IndexPath(row: 0, section: 1),
IndexPath(row: 1, section: 1),
IndexPath(row: 2, section: 1)]
indexPath0 =
[IndexPath(row: 2, section: 0)]
// maybe get a [Array]
[indexPath0, indexPath1]
最佳答案
一个可能的解决方案是首先构建一个字典,其中键是节号,值是该节中 IndexPath
的数组。
let indexPaths = [
IndexPath(row: 0, section: 1),
IndexPath(row: 1, section: 1),
IndexPath(row: 2, section: 1),
IndexPath(row: 2, section: 0),
]
let pathDict = Dictionary(grouping: indexPaths) { (path) in
return path.section
}
然后你可以将这个字典映射到路径数组的数组中。但首先按部分对这些数组进行排序。
let sectionPaths = pathDict.sorted { (arg0, arg1) -> Bool in
return arg0.key < arg1.key // sort by section
}.map { $0.value } // get just the arrays of IndexPath
print(sectionPaths)
输出:
[[[0, 2]], [[1, 0], [1, 1], [1, 2]]]
关于swift - 如何将 indexPath 数组拆分为单独的 indexPath 数组,每个数组的 indexPath 具有相同的 indexPath.section,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55877235/