ios - 奇怪的 json 解码器行为

Question

所以，我有从通知中获得的 userInfo 数据，我想解码这些数据并将其传递给另一个类。我使用 swiftyJSON 作为 json 解码器。这是我的代码:

func decodedNotificationTransactionData(data: Any, completionHandler: @escaping (_ dict: [String : Any]) -> ()){

    let dict = JSON(data)

    print ("this is json data \(dict)")
    print("this is status \(dict["status"])")

    let test = [
        "id" : "\(dict["id"])",
        "orderDate" : "\(dict["orderDate"])",
        "patientName" : "\(dict["patient"]["fullName"])",
        "patientAddress" : "\(dict["patient"]["address"])",
        "caregiverName" : "\(dict["care"]["fullName"])",
        "caregiverAddress" : "\(dict["care"]["address"])",
        "serviceType" : "\(dict["service"]["label"])",
        "status" : "\(dict["status"])",
        "price" : "\(dict["totalAmount"])",
        "otherNote" : "\(dict["otherNote"])",
        "totalService" : dict["detailDatas"].count,
        "serviceLongType" : dict["detailDatas"][0]["type"],
        "jsonContent" : dict
        ] as [String : Any]

    completionHandler(test)

}

this the "print ("this is json data (dict)")" result

json data

当代码到达print("this is json data (dict)")时，数据在那里没有问题，但是当代码到达print("this is status (dict[ "status"])") 它在日志中给出 null。您遇到过同样的问题吗？

Answer 1

快速查看 SwiftyJSON 文档会立即发现错误:

Creates a JSON object.
- parameter object: the object.
- note: this does not parse a String into JSON, instead use init(parseJSON: String).
- returns: the created JSON object

public init(_ object: Any) {

所以你必须使用

let dict = JSON(parseJSON: data)