我收到这个 JSON:
JSON: {
"status_code" : 200,
"status" : "ok",
"data" : [
{
"zona" : "Narvarte",
"hora" : "",
"id_zona" : 1423,
"proxdia" : "Lunes 20 de Febrero, 2017",
"coor" : "(19.452187074041884, -99.1457748413086),(19.443769985032485, -99.14852142333984),(19.443446242121073, -99.13787841796875),(19.450244707639662, -99.13822174072266)",
"dias" : "Lunes"
}, ...]
我存储在这个结构中:
struct RutaItem {
var idZona: Int
var dias: String
var proxDia: String
var hora: String
var coor: String
var zona: String
}
然后我创建了一个 [RutaItem] 数组,用于存储结构
var rutaItemArray = [RutaItem]()
数据存储后,rutaItemArray 中的结构如下所示:
[pixan.RutaItem(idZona: 1423, dias: "Lunes", proxDia: "Lunes 20 de Febrero, 2017", hora: "", coor: "(19.452187074041884, -99.1457748413086),(19.443769985032485, -99.14852142333984),(19.443446242121073, -99.13787841796875),(19.450244707639662, -99.13822174072266)", zona: "Narvarte")...]
我现在需要做的是使用 rutaItemArray.coor
的每个索引中的字符串生成一个 MKPolygonObject,所以首先我需要将长字符串转换为 4 个 CLLocationCoordinate2D 对象并将它们放入每个项目在一个数组中放置 4 个坐标对象,然后使用数组索引生成不同区域的多边形。
谁能帮我解决这个问题?
最佳答案
您可以使用正则表达式模式匹配。 内联解释:
let coordString = "(19.452187074041884, -99.1457748413086), (19.443769985032485, -99.14852142333984),(19.443446242121073, -99.13787841796875),(19.450244707639662, -99.13822174072266)"
// Regular expression pattern for "( ... , ... )"
let pattern = "\\((.+?),(.+?)\\)"
let regex = try! NSRegularExpression(pattern: pattern)
// We need an NSString, compare http://stackoverflow.com/a/27880748/1187415
let nsString = coordString as NSString
// Enumerate all matches and create an array:
let coords = regex.matches(in: coordString, range: NSRange(location: 0, length: nsString.length))
.flatMap { match -> CLLocationCoordinate2D? in
// This closure is called for each match.
// Extract x and y coordinate from match, remove leading and trailing whitespace:
let xString = nsString.substring(with: match.rangeAt(1)).trimmingCharacters(in: .whitespaces)
let yString = nsString.substring(with: match.rangeAt(2)).trimmingCharacters(in: .whitespaces)
// Convert to floating point numbers, skip invalid entries:
guard let x = Double(xString), let y = Double(yString) else { return nil }
// Return CLLocationCoordinate2D:
return CLLocationCoordinate2D(latitude: x, longitude: y)
}
关于swift - 将带有坐标的单个字符串转换为 CLLocationCoordinate2D 数组,并使用该数组在 mapView 中生成多边形,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42285506/