arrays - 根据对象属性的字符串数组过滤对象数组

Question

我有一个对象数组，例如:

让食物 = [apple, orange, peach, pear]。

每个对象看起来像这样:

let apple : Fruit = [
  name: "Apple",
  colors: ["red", "yellow", "green", "orange"]
]

我有另一个字符串数组，food 数组应该被过滤:

let avoid = ["red", "yellow"]

我想从 food 数组创建一个新数组，其中 Fruit 对象不包含任何颜色 在 avoid 数组中。所以在这种情况下，Apple 不会出现在 food 数组中，因为它同时包含 red 和 yellow。

谢谢!

Answer 1

由于您还没有给出任何Fruit对象的定义，我正在考虑一个以供引用。

struct Fruit {
    let name: String
    let colors: [String]
}

创建食物数组，

let apple = Fruit(name: "Apple", colors: ["red", "yellow", "green", "orange"])
let orange = Fruit(name: "Orange", colors: ["red", "green", "orange"])
let peach = Fruit(name: "Peach", colors: ["green", "orange"])
let pear = Fruit(name: "Pear", colors: [ "green"])
let food = [apple, orange, peach, pear]

要使用avoid 数组过滤 food 数组，我们可以使用Set intersection 方法，即

let avoid = ["red", "yellow"]
let filteredFruits = food.filter { return Set($0.colors).intersection(avoid).isEmpty }
print(filteredFruits.map({ $0.name })) //["Peach", "Pear"]

filteredFruits 将包含对象 - pear 和 peach