我在 View Controller 中加载电话联系人时遇到小问题，我成功地在 Tableview 中加载了我的电话联系人姓名和号码，但联系人随机加载姓名，我希望联系人姓名必须是等于数字的字母顺序
这是我的示例代码:
func contactDetail () {
var myPhValue:NSString!
var myPBfirstname:NSString!
let qualityOfServiceClass = QOS_CLASS_BACKGROUND
let backgroundQueue = dispatch_get_global_queue(qualityOfServiceClass, 0)
dispatch_async(backgroundQueue, {
let addressBook : ABAddressBookRef? = ABAddressBookCreateWithOptions(nil, nil).takeRetainedValue()
ABAddressBookRequestAccessWithCompletion(addressBook, { (granted : Bool, error: CFError!) -> Void in
if granted == true {
let allContacts : NSArray = ABAddressBookCopyArrayOfAllPeople(addressBook).takeRetainedValue()
for contactRef:ABRecordRef in allContacts { // first name
myPBfirstname = ABRecordCopyValue(contactRef, kABPersonFirstNameProperty)?.takeRetainedValue() as! NSString? ?? ""
let myPBlastname = ABRecordCopyValue(contactRef, kABPersonLastNameProperty)?.takeRetainedValue() as! NSString? ?? ""
let phonesRef: ABMultiValueRef = ABRecordCopyValue(contactRef, kABPersonPhoneProperty)?.takeRetainedValue() as ABMultiValueRef? ?? ""
var phonesArray = Array<Dictionary<String,String>>()
for var i:Int = 0; i < ABMultiValueGetCount(phonesRef); i++ {
let myPhLabel = ABMultiValueCopyLabelAtIndex(phonesRef, i)?.takeRetainedValue() as NSString? ?? ""
myPhValue = ABMultiValueCopyValueAtIndex(phonesRef, i)?.takeRetainedValue() as! NSString? ?? ""
if myPhLabel.containsString("Mobile") {
}
}
let nameString = " "+(myPBlastname as String)
let nameValues = (myPBfirstname as String)+(nameString as String)
let contactDict : Dictionary = ["name": nameValues,"phone":myPhValue]
self.contactArray.addObject(contactDict)
if self.contactArray.count == 0 {
NSLog("contactValue is Zero")
}
else{
NSLog("count Value %d", self.contactArray.count)
}
}
}
dispatch_async(dispatch_get_main_queue(), { () -> Void in
self.contactTable.hidden = false
self.contactTable.reloadData()
})
})
})
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int
{
return contactArray.count
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell
{
let cell:UITableViewCell = self.contactTable.dequeueReusableCellWithIdentifier("cell") as UITableViewCell!
cell.selectionStyle = UITableViewCellSelectionStyle.None
cell.preservesSuperviewLayoutMargins = false
cell.separatorInset = UIEdgeInsetsZero
cell.layoutMargins = UIEdgeInsetsZero
cell.textLabel!.text = contactArray.valueForKey("name").objectAtIndex(indexPath.row) as? String
return cell
}
最佳答案
正如我从您的代码中假设的那样，您的 contactArray 设置了如下值:
let contactArray = [["name": "tim", "phone": 123], ["name": "adi", "phone": 1234], ["name": "cora", "phone": 456], ["name": "berta", "phone": 678]]
要按名称排序，您可以使用 sort method :
let sortedContactArray = contactArray.sort{ ($0["name"] as! String) < ($1["name"] as! String) }
// result: [["phone": 1234, "name": adi], ["phone": 678, "name": berta], ["phone": 456, "name": cora], ["phone": 123, "name": tim]]
关于ios - 快速按字母顺序加载联系人列表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36302719/