ios - 从 Parse 中检索数组并将它们保存在具有相应值的字典中。 [字符串() : [String]()]

Question

我是这里的初学者，我在从解析中检索数组时遇到问题。 我的问题如下..

我创建了一个名为“TypeOfNumbers”的类

var typeOfNumbers:PFObject = PFObject(className: "TypeOfNumbers")
    typeOfNumbers["type"] = "Prime"
    typeOfNumbers["numbers"] = ["2", "3", "5", "7", "11", "13"]
    typeOfNumbers.saveInBackground()

现在假设我们在“TypeOfNumbers”类中有另一行如下:

var typeOfNumbers:PFObject = PFObject(className: "TypeOfNumbers")
    typeOfNumbers["type"] = "Squares
    typeOfNumbers["numbers"] = ["1", "4", "9", "16", "25"]
    typeOfNumbers.saveInBackground()

现在我想检索这两个数组及其对应的类型..

假设我想检索这些数组并想保存在像这样的字典中:

[素数:[“2”、“3”、“5”、“7”、“11”、“13”]，正方形:[“2”、“3”、“5”、“7” , "11", "13"]]

Answer 1

您可以尝试编写以下代码:

var dictionary = [String:String]
var number = 0
let typeOfNumbersAsArrayOfStrings = typeOfNumbers["numbers"] as! [String]
let typeOfNumbersAsArrayOfStrings2 = typeOfNumbers["numbers"] as! [String]
for object in typeOfNumbersAsArrayOfStrings {
     dictionary["\(object)"] = typeOfNumbersAsArrayOfStrings2[number]
     ++number
}