javascript - 仅针对一项特定功能解析连接超时

Question

下面是我的云代码，我试图在其中创建一个好友数据库，第一个和第三个函数都工作正常，但是 AcceptFriendRequest 函数超时，好像那里没有服务器，错误代码为 100。我我很迷茫，因为这种情况 100% 都会发生。感谢所有帮助。

Parse.Cloud.define("AddFriendRequest", function (request, response) {

var FriendRequest = Parse.Object.extend("FriendsIncoming");

var FRequest = new FriendRequest();

var user = request.user;

var query = new Parse.Query(Parse.User);
query.equalTo("username", request.params.username);
query.find({
    success: function (people) {
        if(people.length == 0)
        {
            response.success(-5);
            return;
        }

        var person = people[0];
        FRequest.set("OwnerID", user.id);
        FRequest.set("TargetFriend", person.id);
        FRequest.set("Status", 0);

        var query = new Parse.Query("FriendsIncoming");
        query.equalTo("OwnerID", user.id);
        query.equalTo("TargetFriendID", person.id);
        query.find({
            success: function (results) {

                if (results.length > 0) {
                    response.success(1);
                    return;
                }
                FRequest.save(null, {
                    success: function (Friend) {
                        response.success(2);
                    },
                    error: function (Friend, error) {
                        response.error(3);
                    }
                });
                response.error(-2);

            },
            error: function () {
                response.error(-1);
            }
        });
    }
    ,
    error: function (Friend, error) {
        response.error(-4);
    }

});


});

Parse.Cloud.define("AcceptFriendRequest", function (request, response) {


var user = request.user;

var query = new Parse.Query("FriendsIncoming");
query.equalTo("OwnerID", user.id);
query.equalTo("TargetFriendID", request.params.TargetFriendID);
query.find({
    success: function (results) {

        if (results.length > 0) {

            response.success(1);
            return;
        }
        FRequest.save(null, {
            success: function (Friend) {
                response.success(2);
            },
            error: function (Friend, error) {
                response.error(3);
            }
        });
        response.error(-2);

    },
    error: function () {
        response.error(-1);
    }
});
});




Parse.Cloud.define("RetrieveFriends", function (request, response) {

var query = new Parse.Query("FriendsAccepted");
var results = [];


query.find().then(function (Friends) {
for (var i = 0; i < Friends.length; i++) {
results.push(Friends[i]);
}

// success has been moved inside the callback for query.find()
response.success(results);
}, function (error) {
// Make sure to catch any errors, otherwise you may see a "success/error not called" error in Cloud Code.
response.error("Could not retrieve Posts, error " + error.code + ": " + error.message);
});
});

Answer 1

似乎 AcceptFriendRequest 中的 FRequest 没有初始化... 将其添加到函数内部。 parse.com 上的超时对于云功能是 15 秒，对于 afterSave 是 3 秒。他们可能会更改它，因为他们正在关闭

var FriendRequest = Parse.Object.extend("FriendsIncoming");
var FRequest = new FriendRequest();