ios - 如何解密来自python的加密字符串？

Question

我从 python 得到一个加密的 base64 字符串。格式为 AES 256 CBC。但是，当我尝试使用 iOS Swift 解密时，它会将解密后的字符串返回为 nil。

# coding=utf-8
import base64
from random import choice
from string import letters

try:
    from Crypto import Random
    from Crypto.Cipher import AES
except ImportError:
    import crypto
    import sys

    sys.modules['Crypto'] = crypto
    from crypto.Cipher import AES
    from crypto import Random


class AESCipher(object):
    def __init__(self, key):
        self.bs = 32
        self.key = key

    def encrypt(self, raw):
        _raw = raw
        raw = self._pad(raw)

        print raw, ';'
        print _raw, ';'

        iv = "".join([choice(letters[:26]) for i in xrange(16)])
        print " iv :", iv
        cipher = AES.new(self.key, AES.MODE_CBC, iv)
        return base64.b64encode(iv + cipher.encrypt(raw))

    def decrypt(self, enc):
        enc = base64.b64decode(enc)
        iv = enc[:AES.block_size]
        cipher = AES.new(self.key, AES.MODE_CBC, iv)
        return self._unpad(cipher.decrypt(enc[AES.block_size:])).decode('utf-8')

    def _pad(self, s):
        a = (self.bs - len(s) % self.bs)
        b = chr(self.bs - len(s) % self.bs)
        return s + a * b

    @staticmethod
    def _unpad(s):
        return s[:-ord(s[len(s) - 1:])]
def encrypt(k, t):
    o = AESCipher(k)
    return o.encrypt(t)


def decrypt(k, t):
    o = AESCipher(k)
    return o.decrypt(t)


def main():
    k = "qwertyuiopasdfghjklzxcvbnmqwerty"
    s1 = "Hello World!"

    d2 = encrypt(k, s1)

    print " Password :", k
    print "Encrypted :", d2
    print "    Plain :", decrypt(k, d2)

if __name__ == '__main__':
    main()

苹果

这里我使用AES256CBC Lib https://github.com/SwiftyBeaver/AES256CBC

let decrypted = AES256CBC.decryptString("Ymdqc3ZqdmZ1cXdsZG1sZenhgr4Xt0+ceARYRh1n40QkNDV/dyKbQjYLcbiXBBeO", password: "qwertyuiopasdfghjklzxcvbnmqwerty")

        print("decrypted: \(String(describing: decrypted))") // here I get nil

当 python 运行时我得到这个日志

iv : bgjsvjvfuqwldmle
 Password : qwertyuiopasdfghjklzxcvbnmqwerty
Encrypted : Ymdqc3ZqdmZ1cXdsZG1sZenhgr4Xt0+ceARYRh1n40QkNDV/dyKbQjYLcbiXBBeO
    Plain : Hello World!

我不知道为什么 python 和 iOS 在 AES 中不一样。任何解决此问题的人请在下面给出答案。提前致谢。

Answer 1

我认为您需要先解码您的 base64 字符串。 也许这会起作用(只是用谷歌搜索，我不是 iOS 开发人员，所以对于最终的错误我很抱歉)

let decodedData = NSData("Ymdqc3ZqdmZ1cXdsZG1sZenhgr4Xt0+ceARYRh1n40QkNDV/dyKbQjYLcbiXBBeO": base64String, options:NSDataBase64DecodingOptions.fromRaw(0)!)
let decodedString = NSString(data: decodedData, encoding: NSUTF8StringEncoding)
let decrypted = AES256CBC.decryptString(decodedString, password: "qwertyuiopasdfghjklzxcvbnmqwerty")
        print("decrypted: \(String(describing: decrypted))")

documentation 中也有说明