我有一个特定的 JSON 节点对应于 import org.codehaus.jackson.JsonNode,而不是 导入 org.codehaus.jackson.map.JsonNode。
[
{
"givenName": "Jim",
"formattedName": "jimJackson",
"familyName": null,
"middleName": "none",
"honorificPrefix": "mr",
"honorificSuffix": "none"
},
{
"givenName": "john",
"formattedName": "johnLasher",
"familyName": null,
"middleName": "none",
"honorificPrefix": "mr",
"honorificSuffix": "none"
},
{
"givenName": "carlos",
"formattedName": "carlosAddner",
"familyName": null,
"middleName": "none",
"honorifiPrefix": "mr",
"honorificSuffix": "none"
},
{
"givenName": "lisa",
"formattedName": "lisaRay",
"familyName": null,
"middleName": "none",
"honorificPrefix": "mrs",
"honorificSuffix": "none"
},
{
"givenName": "bradshaw",
"formattedName": "bradshawLion",
"familyName": null,
"middleName": "none",
"honorificPrefix": "mr",
"honorificSuffix": "none"
},
{
"givenName": "phill",
"formattedName": "phillKane",
"familyName": null,
"middleName": "none",
"honorificPrefix": "mr",
"honorificSuffix": "none"
},
{
"givenName": "Gabriel",
"formattedName": "gabrielMoosa",
"familyName": null,
"middleName": "none",
"honorificPrefix": "mr",
"honorificSuffix": "none"
}
]
我想从上述数组的所有 JSON 节点中删除“familyName”和“middleName”。有什么办法可以做到这一点?
最佳答案
我没有对此进行测试,但我认为这样的事情会做你想要的:
import org.codehaus.jackson.node.ObjectNode;
// ...
for (JsonNode personNode : rootNode) {
if (personNode instanceof ObjectNode) {
ObjectNode object = (ObjectNode) personNode;
object.remove("familyName");
object.remove("middleName");
}
}
您也可以使用 Jackon 的原始解析 API 更有效地执行此操作,但代码会更加困惑。
关于java - 使用 jackson 删除 JSON 元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15603033/