我想要一个正则表达式从字符串中提取 Starboy
和 The Weekend/Daft Punk
:
The Weeknd / Daft Punk - text=\"Starboy\" song_spot=\"M\" MediaBaseId=\"2238986\" itunesTrackId=\"0\" amgTrackId=\"-1\" amgArtistId=\"0\" TAID=\"744880\" TPID=\"43758958\" cartcutId=\"08
到目前为止这是我的尝试
do {
let input = "The Weeknd / Daft Punk - text=\"Starboy\" song_spot=\"M\" MediaBaseId=\"2238986\" itunesTrackId=\"0\" amgTrackId=\"-1\" amgArtistId=\"0\" TAID=\"744880\" TPID=\"43758958\" cartcutId=\"0893584001\""
let regex = try NSRegularExpression(pattern: "text=\"(.*)", options: NSRegularExpression.Options.caseInsensitive)
let matches = regex.matches(in: input, options: [], range: NSRange(location: 0, length: input.utf16.count))
if let match = matches.first {
let range = match.range(at:1)
if let swiftRange = Range(range, in: input) {
let name = input[swiftRange]
print(name)
}
}
} catch {
print("Regex was bad!")
}
但这给了我整个字符串
Starboy" song_spot="M" MediaBaseId="2238986" itunesTrackId="0" amgTrackId="-1" amgArtistId="0" TAID="744880" TPID="43758958" cartcutId="0893584001"
最佳答案
如果您需要捕获序列 - text=
之前的所有文本后跟引号之间的任何单词,您可以使用此正则表达式 ".*(?=(text=\"[\\w\\s]+\"))"
并捕获序列 text="
之后的任何单词你可以使用这个正则表达式 "(?<=text=\")([\\w\\s]+)"
.如果您想捕获两个范围,只需使用“|”它们之间如下:
let string = """
The Weeknd / Daft Punk - text=\"Starboy\" song_spot=\"M\" MediaBaseId=\"2238986\" itunesTrackId=\"0\" amgTrackId=\"-1\" amgArtistId=\"0\" TAID=\"744880\" TPID=\"43758958\" cartcutId=\"08
"""
let pattern = ".*(?=( - text=\"[\\w\\s]+\"))|(?<=text=\")([\\w\\s]+)"
do {
let regex = try NSRegularExpression(pattern: pattern, options: .caseInsensitive)
let matches = regex.matches(in: string, options: [], range: NSRange(location: 0, length: string.utf16.count))
for match in matches {
if let range = Range(match.range, in: string) {
let name = string[range]
print(name)
}
}
} catch {
print("Regex was bad!")
}
这将打印
The Weeknd / Daft Punk
Starboy
关于regex - 在swift中使用正则表达式从句子内部提取单词,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46869167/