当我保存用户创建的项目时,我使用以下代码:
let ref = Database.database().reference(fromURL: "https://projectsupport-e475b.firebaseio.com/").child("Projects").childByAutoId()
let values = ["ProjectTitle": ProjectTitle, "Fighters": EarlySupporters, "Tags": Tags, "TotalFighters": "0", "Description": Description, "ProfileImage": profileImageUrl, "Creator": self.username!] as [String : Any]
ref.updateChildValues(values)
这是我的数据库:
Projects:
|
-------KyHzk8VtHitcLlYw1MT
|
- ProjectName: "ProjectNameTest"
|
- Creator: "CreatorTest"
- And so on...
当我尝试检索数据时,我使用以下代码:
Database.database().reference().child("Projects").observe(.childAdded, with: { (snapshot) in
if let dictionary = snapshot.value as? [String : AnyObject]
{
let project = Project(dictionary: dictionary)
//The following line was the problem:
//project.setValuesForKeys(dictionary)
//I'm still not sure why that solved the problem.
print(project)
DispatchQueue.main.async {
self.tableView.reloadData()
}
}
print(snapshot)
}, withCancel: nil)
这会导致崩溃,如下所示:
Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[ setValue:forUndefinedKey:]: this class is not key value coding-compliant for the key Creator.'
我如何访问数据?我如何获得 key ?
最佳答案
我明白了!我认为这些代码行存在一些问题:
let project = Project(dictionary: dictionary)
project.setValuesForKeys(字典)
你的变量 project 是什么类型? 在它前面加上 let
关键字,你是说你的 project
变量是一个不可变类型。设置后,您将无法修改它。而且,这正是您在下一行使用函数 setValueForKeys
尝试执行的操作。尝试使用 var project = Project(dictionary: dictionary)
将 project
设为可变类型,看看是否有任何区别。
关于swift - 如何达到 childByAutoId() 背后的值(value),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47205093/