这是我向 php 发出 Json 请求并在应用程序中显示数据的代码:
import Foundation
protocol FeedmodelProtocol: class {
func itemsDownloaded(items: NSArray)
}
class Feedmodel: NSObject, URLSessionDataDelegate {
weak var delegate: FeedmodelProtocol!
func downloadItems() {
let myUrl = URL(string: "http://www.example.net/zumba.php");
var request = URLRequest(url:myUrl!)
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.httpMethod = "POST"
let postString = "firstName=51&lastName=6";
request.httpBody = postString.data(using: .utf8)
let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data, error == nil else { // check for fundamental networking error
print("error=\(String(describing: error))")
return
}
if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 { // check for http errors
print("statusCode should be 200, but is \(httpStatus.statusCode)")
print("response = \(String(describing: response))")
}
let responseString = String(data: data, encoding: .utf8)
print("responseString = \(String(describing: responseString))")
self.parseJSON(data)
}
task.resume()
}
func parseJSON(_ data:Data) {
var jsonResult = NSArray()
do{
jsonResult = try JSONSerialization.jsonObject(with: data, options:JSONSerialization.ReadingOptions.allowFragments) as! NSArray;
} catch let error as NSError {
print(error)
}
var jsonElement = NSDictionary()
let stocks = NSMutableArray()
for i in 0 ..< jsonResult.count
{
print(jsonResult)
jsonElement = jsonResult[i] as! NSDictionary
let stock = Stockmodel()
//the following insures none of the JsonElement values are nil through optional binding
if let Datum = jsonElement["Datum"] as? String,
let Tankstelle = jsonElement["Tankstelle"] as? String,
let Kraftstoff1 = jsonElement["Kraftstoff1"] as? String,
let Preis1 = jsonElement["Preis1"] as? String,
let Kraftstoff2 = jsonElement["Kraftstoff2"] as? String,
let Preis2 = jsonElement["Preis2"] as? String,
let Notiz = jsonElement["Notiz"] as? String,
let longitude = jsonElement["longitude"] as? String,
let latitude = jsonElement["latitude"] as? String
{
print (Datum)
print(Tankstelle)
print(Kraftstoff1)
print(Preis1)
print(Kraftstoff2)
print(Preis2)
print(Notiz)
print(longitude)
print(latitude)
stock.Datum = Datum
stock.Tankstelle = Tankstelle
stock.Kraftstoff1 = Kraftstoff1
stock.Preis1 = Preis1
stock.Kraftstoff2 = Kraftstoff2
stock.Preis2 = Preis2
stock.Notiz = Notiz
stock.longitude = longitude
stock.latitude = latitude
}
stocks.add(stock)
}
DispatchQueue.main.async(execute: { () -> Void in
self.delegate.itemsDownloaded(items: stocks)
})
}
}
我有一个 mySQL PHP，它似乎可以工作，因为我的控制台向我显示:
responseString = Optional("[\"51\",\"6\"]") ( 51, 6 ) Could not cast value of type 'NSTaggedPointerString' (0x1045cbf68) to 'NSDictionary' (0x1045cc288). 2018-06-20 23:29:34.586355+0200 TankBilliger[37631:3753628] Could not cast value of type 'NSTaggedPointerString' (0x1045cbf68) to 'NSDictionary' (0x1045cc288). (lldb)
我不知道是什么问题，有人可以帮忙吗？
谢谢!
最佳答案
问题是，您将数据作为字典获取，但您将其作为字符串
删除这一行再试试
let responseString = String(data: data, encoding: .utf8)
print("responseString = \(String(describing: responseString))")
此方法 parseJSON() 完成上述功能
关于php - 我在 Swift 中对 PHP 的 Json 请求出错，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50957354/