ios - 如何从 swift 4.2 中的通知传递 url 以在 webview 中打开

Question

到目前为止，在我的委托(delegate)中，我已经能够从通知中成功获取 URL，我遇到的问题是如何将 url 传递给我的 viewcontroller.swift 以在 webview 中打开 url。我已经尝试了堆栈中的几个示例，但它们似乎不适用于 swift 4.2。谁能帮我？对不起，我是 swift 的新手。

AppDelegate.swift

func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable : Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {

    let data = userInfo as! [String: AnyObject]

    let state = UIApplication.shared.applicationState

    if state == .background {
        // background
        print("==== Active Running ====")
        if let aps = data["aps"] {
            let url = aps["url"]
        }
    }
    else if state == .inactive {
        // inactive
        print("==== Inactive Running ====")
        if let aps = data["aps"] {
            let url = aps["url"]
        }
    }
    else if state == .active {
        // foreground
        print("==== Foreground Running ====")
        if let aps = data["aps"] {
            let url = aps["url"]
        }
    }
}

Answer 1

如果你打算从头开始初始化那个 View Controller ，你可以在你的 Appdelegate 中这样做，你可以通过以下方式获得你的 URL:

        let storyBoard = UIStoryboard(name: "Main", bundle: nil)
        let vc = storyBoard.instantiateViewController(withIdentifier: "yourViewControllerID") as! YourViewController
        vc.url = url
        self.window?.rootViewController = vc

同样在 YourViewController 文件中，将您的 url 设置为:

var url = "" {
    didSet {
       //trigger your webView to start loading, you can also do it at viewDidAppear maybe.
       //example:
       let url = URL(string: url)
       let request = URLRequest(url: url)
       webView.loadRequest(request)
    }
}