javascript - 如何将参数传递给 JQuery $.getJSON 回调方法？

Question

 function CallMethod() {
     $.getJSON('/website/RESTfulService.svc/LiveLocation/json?{x=1,y=2}', function(data) {
         getResult(data.lat, data.lon);
     });
 }

Answer 1

在 URL 之后和函数之前将它们作为对象传递:

function CallMethod() {
     $.getJSON('/website/RESTfulService.svc/LiveLocation/json', 
     {
        x: "1",
        y: "2"
     }, 
     function(data) {
         getResult(data.lat, data.lon);
     });
}