swift - 如何在 iPhone 电池电量为 10% 时收到通知

Question

我正在构建一个 Apple Watch 应用程序，让您可以看到 iPhone 电池电量， 这是获取电池电量的代码:

 UIDevice.currentDevice().batteryMonitoringEnabled = true
 batteryLevel = UIDevice.currentDevice().batteryLevel

现在如何在 iPhone 电池电量为 10% 时调用通知？ 谢谢

Answer 1

这是 Objective-C 但很容易翻译成 Swift:

    [[UIDevice currentDevice] setBatteryMonitoringEnabled:YES];
    float battery = [[UIDevice currentDevice] batteryLevel];

    if (battery < alertLevel) {
        //Send notification   
    }

如何发送 UILocalNotification

        UILocalNotification *notification = [[UILocalNotification alloc] init];
        notification.fireDate = [NSDate dateWithTimeIntervalSinceNow:0];
        notification.alertBody = @"WARNING!";
        notification.timeZone = [NSTimeZone defaultTimeZone];
        notification.soundName = UILocalNotificationDefaultSoundName;
        notification.applicationIconBadgeNumber = 0;
        NSDictionary *infoDict = [NSDictionary dictionaryWithObject:@"Low battery!" forKey:@"Notification"];
        notification.userInfo = infoDict;
        [[UIApplication sharedApplication] scheduleLocalNotification:notification];