我有以下对象,然后想合并。
var prop1 = [AnyHashable: Any]()
prop1["key1"] = "Phase3"
prop1["key2"] = "405"
var prop2 = [AnyHashable: Any]()
prop2["key3"] = "Phase1"
prop2["key4"] = "45"
我想要一个最终对象 prop1+prop2
一个 [AnyHashable: Any]()
,最好的方法是什么?
最佳答案
你可以写
let union = Array(prop2.keys).reduce(prop1) { (dict, key) -> [AnyHashable:Any] in
var dict = dict
dict[key] = prop2[key]
return dict
}
例子
var prop1 = [AnyHashable: Any]()
prop1["key1"] = "Phase3"
prop1["key2"] = "405"
var prop2 = [AnyHashable: Any]()
prop2["key3"] = "Phase1"
prop2["key4"] = "45"
let union = Array(prop2.keys).reduce(prop1) { (dict, key) -> [AnyHashable:Any] in
var dict = dict
dict[key] = prop2[key]
return dict
}
dump(union) //
重复
请注意,如果两个字典中存在相同的键,结果将从 prop2
中获取该特定键的值。
例子
let prop1 : [AnyHashable: Any] = ["key1": "value from prop1"]
let prop2 : [AnyHashable: Any] = ["key1": "value from prop2"]
let union = Array(prop2.keys).reduce(prop1) { (dict, key) -> [AnyHashable:Any] in
var dict = dict
dict[key] = prop2[key]
return dict
}
print(union) // [AnyHashable("key1"): "value from prop2"]
关于swift - 合并/追加 [AnyHashable : Any]() on Swift 3,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44294588/