swift - 在变量中快速创建对象/实例

Question

我不知道在 Swift 中创建实例或寻址它们时如何使用变量: 例如，我如何在循环中执行以下操作(创建实例):

class Guest {
    let name: String
    var age: Int 
    init(name: String, age: Int) {
        self.name = name
        self.age = age
    }
}

let guests = [["ann", 1] , ["bob", 2] ...]

使循环等于:

let ann = Guest(name: "ann" , age: 1)
let bob = Guest(name: "bob" , age: 2)
...

编辑:我正在寻找这样的东西:

for i in guests {
  let i[0] = Guest(name: i[0] , age: i[1])   

寻址示例:

print(guests[0].age)
>>>1

我进行了很多搜索，但得到了关于在类中创建变量的问题。

非常感谢!

Answer 1

您可以使用经典循环来做到这一点:

let input = [("Ann", 1), ("Bob", 2)]

var guests: [Guest] = []
for each in input {
    guests.append(Guest(name: each.0, age: each.1))
}

但是，可以使用函数技术更简洁地完成此操作(并避免使用 var):

let guest = [("Ann", 1), ("Bob", 2)].map { Guest(姓名: $0.0, 年龄: $0.1) }

编辑:基于字典的解决方案(Swift 4；对于 Swift 3 版本只需使用经典循环)

let input = [("Ann", 1), ("Bob", 2)]
let guests = Dictionary(uniqueKeysWithValues: input.map {
    ($0.0, Guest(name: $0.0, age: $0.1))
})

或者，如果两个客人可以同名:

let guests = Dictionary(input.map { ($0.0, Guest(name: $0.0, age: $0.1)) }) { first, second in
    // put code here to choose which of two conflicting guests to return
    return first
}

有了字典，你可以这样做:

if let annsAge = guests["Ann"]?.age {
    // do something with the value
}