ios - 访问方法内部的变量并允许使用 segue 将其传递给其他 View Controller

Question

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell{
let cell = collectionView.dequeueReusableCell(withReuseIdentifier: cellIdentifier, for: indexPath) as! FeedCollectionViewCell
cell.postTextView.text = posts.reversed()[indexPath.row].caption
cell.postImageView.image = UIImage(named: "photoplaceholder.jpg")
cell.priceTextView.text = posts.reversed()[indexPath.row].price
cell.categoryTextView.text = posts.reversed()[indexPath.row].category
cell.usernameLabel.text = posts.reversed()[indexPath.row].username
cell.buttonEvents = {
    let storyboard = UIStoryboard(name: "Main" , bundle: nil)
    let chatViewController =
        storyboard.instantiateViewController(withIdentifier: "chat")
    self.present(chatViewController, animated: true,completion: nil)
    var receiverIDNumber = cell.usernameLabel.text
}

我想将 receiverIDNumber 传递给另一个 View Controller ，但是我做不到，因为变量在方法内部。

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

    let chatViewController = segue.destination as! ChatViewController


    chatViewController.receivedString = receiverIDNumber
}

Answer 1

您可以试试这个，因为 prepareForSegue 仅由 performSegue 触发，而不是 present

let chatViewController = storyboard.instantiateViewController(withIdentifier: "chat") as! ChatViewController
chatViewController.receivedString = cell.usernameLabel.text
self.present(chatViewController, animated: true,completion: nil)