我有这段代码(见下文),但我无法回显变量。第 5 行是 echo ,在 echo 中是 html 的负载(我已经将引号转义)和变量的负载。我无法让变量在主回显中回显。
更新: 此外,还有一个需要考虑的 onclick。
<?php
if(
in_array("Branding", get_field('categories')) && $grid_title == "Branding"
){
echo "
<div class=\"grid-box\" onclick=\"location.href='<?php echo get_page_link($post->ID) ?>';\" style=\"cursor: pointer;\">
<div class=\"phase-1\">
<img class=\"grid-image\" src=\"<?php echo $fields->thumb_image; ?>\" alt=\"<?php echo $fields->company_name; ?>\" height=\"152\" width=\"210\" />
<div class=\"grid-heading\">
<h2><?php echo $fields->company_name; ?></h2>
<h3><?php echo implode(', ',get_field('categories'));?></h3>
</div>
</div>
<div class=\"phase-2\">
<div class=\"grid-info\">
<h4><?php echo $fields->project_name; ?></h4>
<p><?php echo $fields->description; ?></p>
</div>
<div class=\"grid-heading-hover\">
<h2><?php echo $fields->company_name; ?></h2>
<h3><?php echo implode(', ',get_field('categories'));?></h3>
</div>
</div>
</div>
";
}
?>
最佳答案
你不能在 echo 中使用 echo ,你只需要像这样正确地连接你的字符串:
$Content = "
<div class=\"grid-box\" onclick=\"location.href='" . get_page_link($post->ID). "';\" style=\"cursor: pointer;\">
<div class=\"phase-1\">
<img class=\"grid-image\" src=\"" . $fields->thumb_image . "\" alt=\"" . $fields->company_name. "\" height=\"152\" width=\"210\" />
<div class=\"grid-heading\">
<h2> " . $fields->company_name . "</h2>
<h3>" . implode(', ',get_field('categories')) . "</h3>
</div>
</div>
<div class=\"phase-2\">
<div class=\"grid-info\">
<h4>" . $fields->project_name . "</h4>
<p>" . $fields->description . "</p>
</div>
<div class=\"grid-heading-hover\">
<h2>" . $fields->company_name . "</h2>
<h3>" . implode(', ',get_field('categories')). "</h3>
</div>
</div>
</div>";
echo $Content;
关于php - echo html 和变量的语法帮助,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6057153/