json - 快速创建 JSON

Question

我需要像这样创建 JSON:

Order = {   type_id:'1',model_id:'1',

   transfer:{
     startDate:'10/04/2015 12:45',
     endDate:'10/04/2015 16:00',
     startPoint:'Ул. Момышулы, 45',
     endPoint:'Аэропорт Астаны'
   },
   hourly:{
     startDate:'10/04/2015',
     endDate:'11/04/2015',
     startPoint:'ЖД Вокзал',
     endPoint:'',
     undefined_time:'1'
   },
   custom:{
     startDate:'12/04/2015',
     endDate:'12/04/2015',
     startPoint:'Астана',
     endPoint:'Павлодар',
     customPrice:'50 000'
   },
    commentText:'',
    device_type:'ios'
};

问题是我无法创建有效的 JSON。 以下是我创建对象的方式:

let jsonObject: [AnyObject]  = [
        ["type_id": singleStructDataOfCar.typeID, "model_id": singleStructDataOfCar.modelID, "transfer": savedDataTransfer, "hourly": savedDataHourly, "custom": savedDataReis, "device_type":"ios"]
    ]

其中 savedData 是字典:

let savedData: NSDictionary = ["ServiceDataStartDate": singleStructdata.startofWork, 
"ServiceDataAddressOfReq": singleStructdata.addressOfRequest, 
"ServiceDataAddressOfDel": singleStructdata.addressOfDelivery, 
"ServiceDataDetailedText": singleStructdata.detailedText, "ServiceDataPrice": singleStructdata.priceProposed]

当我只使用字符串创建我的 JSON 对象时，一切正常。但是，当我包含字典 NSJSONSerialization.isValidJSONObject(value) 时，返回 false。如何创建有效的字典？

Answer 1

一个问题是这段代码不是Dictionary类型的。

let jsonObject: [Any]  = [
    [
         "type_id": singleStructDataOfCar.typeID,
         "model_id": singleStructDataOfCar.modelID, 
         "transfer": savedDataTransfer, 
         "hourly": savedDataHourly, 
         "custom": savedDataReis, 
         "device_type":"iOS"
    ]
]

上面是 AnyObject 的 Array，其中包含 [String: AnyObject] 类型的 Dictionary它。

尝试这样的方式来匹配您在上面提供的 JSON:

let savedData = ["Something": 1]

let jsonObject: [String: Any] = [ 
    "type_id": 1,
    "model_id": 1,
    "transfer": [
        "startDate": "10/04/2015 12:45",
        "endDate": "10/04/2015 16:00"
    ],
    "custom": savedData
]

let valid = JSONSerialization.isValidJSONObject(jsonObject) // true