我有显示多种咖啡值的 JavaScript 代码。 如果我试图显示单值咖啡,它不会进入 else if。 我修改了现有代码但出现未定义错误。 你能告诉我如何解决吗?
var multCoffees = false;
var singleCoffee = false;
if (Coffees.length > 1) {
multCoffees = true;
}
if (Coffees.length > 1) {
singleCoffee = true;
}
if (apptTimeCell) {
apptTimeHTML = MyDay.dish(allData, multCoffees, singleCoffee);
apptTimeCell.innerHTML = apptTimeHTML;
} else {
apptTimeCell = Util.cep("span", {
className: "appt-time"
});
patientRowTD.insertBefore(apptTimeCell, patCell);
}
dish: function (allData, multCoffees, singleCoffee) {
if (multCoffees) {
var htmlArr = [];
htmlArr.push(allData.APPT_TIME_DISPLAY, "<br/><span class='sub-detail'>", allData.MNEMONIC, "</span>");
console.log("multiCoffee" + allData.PROVIDER_MNEMONIC);
return htmlArr.join("");
} else if (singleCoffee) {
console.log("inside if" + allData.PROVIDER_MNEMONIC);
var htmlArr = [];
htmlArr.push(allData.APPT_TIME_DISPLAY, "<br/><span class='sub-detail'>", allData.PROVIDER_MNEMONIC, "</span>");
console.log("singleCoffee" + allData.PROVIDER_MNEMONIC);
return htmlArr.join("");
} else {
return allData.APPT_TIME_DISPLAY;
}
},
工作代码:
var multCoffees = false;
if (Coffees.length > 1) {
multCoffees = true;
}
if (apptTimeCell) {
apptTimeHTML = MyDay.dish(allData, multCoffees);
apptTimeCell.innerHTML = apptTimeHTML;
} else {
apptTimeCell = Util.cep("span", {
className: "appt-time"
});
patientRowTD.insertBefore(apptTimeCell, patCell);
}
dish: function (allData, multCoffees) {
if (multCoffees) {
var htmlArr = [];
htmlArr.push(allData.APPT_TIME_DISPLAY, "<br/><span class='sub-detail'>", allData.MNEMONIC, "</span>");
console.log("multiCoffee" + allData.PROVIDER_MNEMONIC);
return htmlArr.join("");
} else {
return allData.APPT_TIME_DISPLAY;
}
},
最佳答案
假设 Coffees.length 是 2。你这样做......
if (Coffees.length > 1) {
multCoffees = true;
}
...和 2 > 1,所以现在 multCoffees 为真,但随后您执行此操作,它会检查相同的事情...
if (Coffees.length > 1) {
singleCoffee = true;
}
并且,由于 2 > 1 仍然存在,现在 multCoffee 和 singleCoffee 都为真。所以当你尝试做的时候
if (multCoffees) {
...
} else if (singleCoffee) {
...
}
第一个 if 分支为 true,因此它被执行,else 分支因此被忽略(尽管也为 true)。您可能打算从
开始if (Coffees.length == 1) {
singleCoffee = true;
} else if (Coffees.length > 1) {
multCoffees = true;
}
关于javascript - else if 不打印控制台值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18151045/