我的代码出现错误:
ExecuteNonQuery:连接属性尚未初始化。
这可能是由于此代码中的行:
OdbcCommand cmd = new OdbcCommand("INSERT INTO Pictures (UserID, picturepath) VALUES ('" + theUserId + "' , '" + fileuploadpath + "')");
完整代码:
{
string theUserId = Session["UserID"].ToString();
{
OdbcConnection cn = new OdbcConnection("Driver={MySQL ODBC 3.51 Driver}; Server=localhost; Database=gymwebsite2; User=root; Password=commando;");
cn.Open();
}
if (FileUploadControl.HasFile)
{
try
{
string filename = Path.GetFileName(FileUploadControl.FileName);
//FileUploadControl.SaveAs(Server.MapPath("~/userdata/" + theUserId + "/uploadedimage/") + filename);
string fileuploadpath = Server.MapPath("~/userdata/" + theUserId + "/uploadedimage/");
FileUploadControl.SaveAs(Path.Combine(fileuploadpath, filename));
StatusLabel.Text = "Upload status: File uploaded!";
OdbcCommand cmd = new OdbcCommand("INSERT INTO Pictures (UserID, picturepath) VALUES ('" + theUserId + "' , '" + fileuploadpath + "')");
cmd.ExecuteNonQuery();
}
catch (Exception ex)
{
StatusLabel.Text = "Upload status: The file could not be uploaded. The following error occured: " + ex.Message;
}
}
}
}
还有另一个问题,我不认为它是我想要的插入,因为这将在我的数据库中创建重复条目,是否只是将它从 INSERT INTO 更改为 UPDATE?
还有上传图片时可以覆盖的方法吗? Atm 它只是将图像保存到与我已有的文件夹相同的文件夹中吗?第一张图片或任何图片显然不会具有相同的文件名,那么我将如何用我上传的图片覆盖文件夹中的任何图片?
编辑:
新错误(fileupload 工作因为它存储在正确的区域但是将 fileupload 传递给插入语句有点不稳定)
我得到了错误
无法上传文件。发生以下错误:错误 [42000] [MySQL][ODBC 3.51 驱动程序][mysqld-5.5.9]您的 SQL 语法有误;检查与您的 MySQL 服务器版本对应的手册,了解在第 1 行的 ''C:\Users\Garrith\Documents\Visual Studio 2010\WebSites\WebSite1\userdata\1\uplo' 附近使用的正确语法
哪个有点奇怪?
我试图做的就是将文件路径+文件名保存在 mydb 中,我试图传递给插入的尝试显然失败了。
protected void UploadButton_Click(object sender, EventArgs e)
{
if (FileUploadControl.HasFile)
{
try
{
string theUserId = Session["UserID"].ToString();
OdbcConnection cn = new OdbcConnection("Driver={MySQL ODBC 3.51 Driver}; Server=localhost; Database=gymwebsite2; User=root; Password=commando;");
cn.Open();
string filename = Path.GetFileName(FileUploadControl.FileName);
//FileUploadControl.SaveAs(Server.MapPath("~/userdata/" + theUserId + "/uploadedimage/") + filename);
string fileuploadpath = Server.MapPath("~/userdata/" + theUserId + "/uploadedimage/");
FileUploadControl.SaveAs(Path.Combine(fileuploadpath, filename));
StatusLabel.Text = "Upload status: File uploaded!";
//some kind of function to take the path then enter it into my insert syntax?
OdbcCommand cmd = new OdbcCommand("INSERT INTO Pictures (UserID, picturepath) VALUES ('" + theUserId + "' , '" + fileuploadpath + "')", cn);
cmd.ExecuteNonQuery();
}
catch (Exception ex)
{
StatusLabel.Text = "Upload status: The file could not be uploaded. The following error occured: " + ex.Message;
}
}
}
}
正如您在这一行中看到的:
VALUES ('" + theUserId + "' , '" + fileuploadpath + "')", cn);
我缺少“文件名”我试过这个:
VALUES ('" + theUserId + "' , '" + fileuploadpath, filename + "')", cn);
便宜的镜头哈哈,但我想值得一试,它像往常一样哭了!
最佳答案
您需要将连接与 cmd 相关联:
OdbcCommand cmd =
new OdbcCommand("INSERT INTO Pictures (UserID, picturepath) VALUES ('" + theUserId + "' , '" + fileuploadpath + "')");
cmd.Connection = cn; // <--------
cmd.ExecuteNonQuery();
另外,去掉这里的大括号:
{
OdbcConnection cn = new OdbcConnection("Driver={MySQL ODBC 3.51 Driver};
Server=localhost; Database=gymwebsite2; User=root; Password=commando;"); cn.Open();
}
关于c# - 执行非查询 : Connection property has not been initialized?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5427945/