我设置了一个 php 页面，以便用户可以单击链接进行登录，然后会弹出一个带有登录凭据的弹出窗口 (signin.php)。当他们填写信息并单击按钮登录时，信息在 signinfinal.php 中得到验证。当他们正确登录时，我正在尝试创建一个 session 。因此，当他们登录或关闭弹出窗口时，我希望他们所在的主页 (index.php) 刷新，我希望“登录 |注册”链接更改为“嗨，(用户名)!”我将所有这些设置为一个名为“$var”的 php 变量，该变量中包含一些 javascript。
奇怪的是，我可以在我的计算机上的多个浏览器上注册和登录，并且页面会刷新并正确存储我的 session ，但其他用户报告说即使在刷新页面后 session 也无法正常工作。这是一个棘手的问题，如果有人可以帮助我解决它，我将不胜感激。
这是 index.php 顶部的代码...
<?php
// this starts the session
session_start();
$var = "";
$varcontact = "<a href='JavaScript:newPopup(\"http://www.yourfantasyfootballrealit.com/contact.php\");' class='three'>Contact</a>";
// echo variable from the session, we set this on our other page
if ($_SESSION['userid'] == "") {
$var = "<a href='JavaScript:newPopup(\"http://www.yourfantasyfootballrealit.com/register.html\");' class='two'>Register</a> | <a href='JavaScript:newPopup(\"http://www.yourfantasyfootballrealit.com/signin.php\");' class='two'>Sign In</a>";
} else {
$var = "Hello, ".$_SESSION['userid'] ."! | " . "<a href=\"http://www.yourfantasyfootballreality.com/logout.php\" class='two'>Log Out</a>";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<script src="jquery-1.8.1.js"></script>
<script src="jquery.easing-1.3.pack.js"></script>
<script src="jquery-easing-compatibility.1.2.pack.js"></script>
<script src="coda-slider.1.1.1.pack.js"></script>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="icon" href="http://www.indiana.edu/favicon.ico" />
<title>YourFantasyFootballReality</title>
<link rel="stylesheet" type="text/css" href="mystyle.css" />
<script type="text/javascript">
// Popup window code
function newPopup(url) {
popupWindow = window.open(url,'popUpWindow','height=450,width=600,left=10,top=10,resizable=no,scrollbars=yes,toolbar=yes,menubar=no,location=no,directories=no,status=yes')
}
function closeWin() {
document.write("<p>This is 'myWindow'</p>");
}
</script>
</head>
<body>
<!--Login and Register links-->
<div class="enter">
<?=$var?>
</div>
这是 signin.php 的所有代码
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head><title>Sign In</title></head>
<body onunload="window.opener.location.reload();">
<h1>Sign In</h1>
<form action="signinfinal.php" method="POST">
<table cellpadding="2" cellspacing="0" border="0">
<tr>
<td width="130"> User ID: </td>
<td width="140"> <input name="UserID" type="text"> </td>
<td width="300" rowspan="7" valign="top"> </td>
</tr>
<tr><td> Password: </td>
<td><input name="Password" type="password" size="15"></td>
</tr>
<tr>
<td colspan="2"><input type="submit" value="Sign In" name="action">
</td>
</tr>
</table>
</form>
</body>
</html>
这里是 signinfinal.php 的所有代码...
<?php
session_start();
//$id = $_SESSION['userid'];
//$pw = $_SESSION['password'];
//this connects to the database
$con = mysql_connect("localhost","yourfan_jeengle","armyjoe");
mysql_select_db("yourfan3_demo", $con);
//this is the info the user entered stored as variables
$UserID = $_POST["UserID"];
$Password = $_POST["Password"];
$Action = $_POST["action"];
//this filters throught the variables to check against mysql injections
$UserID = (filter_var($UserID, FILTER_SANITIZE_STRING));
$UserID = (filter_var($UserID, FILTER_SANITIZE_URL));
$Password = (filter_var($Password, FILTER_SANITIZE_STRING));
$Password = (filter_var($Password, FILTER_SANITIZE_URL));
//this is the variables that displays errors and correct instructions
$errors = "";
//this gets the password from the userid entered by user
$result = mysql_query("SELECT Password FROM Users WHERE User_ID = '$UserID'");
$row = mysql_fetch_array($result);
$newresult = $row['Password'];
if (strcmp($Action, "Sign In") == 0) {
//this what happens when the user enters data for the first time and the info is wrong
if (($newresult == $Password) && (($UserID) && ($Password))) {
$greeting = "Welcome, " . $UserID;
$_SESSION['userid'] = $UserID;
$what="Log Out";
} else {
$errors .= "<li> Incorrect Credentials!";
$what="Sign In";
}
if ($errors) { $color = "#ffcccc"; $fontColor = "brown"; }
} else {
header("Location: http://www.yourfantasyfootballrealit.com/logout.php");
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head><title>Sign In</title></head>
<body onunload="window.opener.location.reload();">
<h1>Sign In</h1>
<?=$greeting?>
<form action="signinfinal.php" method="POST">
<table cellpadding="2" cellspacing="0" border="0">
<tr>
<td width="130"> User ID: </td>
<td width="140"> <input name="UserID" type="text" value="<?=$UserID?>"></td>
<td bgcolor="<?=$color?>" width="300" rowspan="7" valign="top"><font color=<?=$fontColor?>><ul> <?=$errors?></font> </ul> </td>
</tr>
<tr> <td> Password: </td><td><input name="Password" type="password" size="15" value="<?=$Password?>"></td></tr>
<tr><td colspan="2"><input type="submit" value="<?=$what?>" name="action">
</tr>
</table>
</form>
</body>
</html>
如有必要，这里是 logout.php 中的内容...
<?php
session_start();
session_destroy();
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
<title>Log Out</title>
<script language="JavaScript">
var time = null
function move() {
window.location = 'http://www.yourfantasyfootballreality.com'
}
</script>
<!--<meta http-equiv="REFRESH" content="1;url=http://www.yourfantasyfootballreality.com/"></HEAD>-->
<BODY>
<body onload="timer=setTimeout('move()',000)">
<script language="javascript">
<!--
setTimeout("self.close();",0000)
//-->
</script>
</BODY>
</HTML>
最佳答案
我认为 signinfinal.php 中的条件应该是，您在成功登录到 logout.php 后发送用户。所以改变条件。
if (!$errors) { $color = "#ffcccc"; $fontColor = "brown"; }
} else {
header("Location: http://www.yourfantasyfootballrealit.com/logout.php");
}
关于PHP session 页面刷新不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12285755/