我有一个基于 JQuery Mobile 的 HTML5 移动应用程序。它不从服务器获取任何内容，有时会连接到互联网，但也有离线模式。 Google Analytics 是否支持离线模式？请注意，我没有使用 Android/iOS SDK。 JQueryMobile 页面中的 ga.js。谢谢
下面是我的 html5 JQueryMobile 代码:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>Mobile @ Your Library</title>
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.0/jquery.mobile-1.0.min.css" />
<script type="text/javascript" src="http://code.jquery.com/jquery-1.6.4.min.js"> </script>
<script type="text/javascript" src="http://code.jquery.com/mobile/1.0/jquery.mobile-1.0.min.js"></script>
<script type="text/javascript">
var _gaq = _gaq || [];
_gaq.push(['_setAccount', 'UA-40418-saddf']);
_gaq.push(['_gat._anonymizeIp']);
(function() {
var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/u/ga_debug.js';
var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
})();
</script>
</script>
<body>
<div data-role="header" data-theme="d">
<h1>Mobile @ Your Library</h1>
<a href="#home" data-icon="home" data-iconpos="notext" data-theme="d" class="ui-btn-right">home</a>
</div><!-- /header -->
<div data-role="content">
<ul data-role="listview" data-inset="true">
<li><a href="#search">Search</a></li>
<li><a href="#hours">Hours</a></li>
<li><a href="#ask">Ask a Librarian</a></li>
<li><a href="#about">About</a></li>
<li><a href="#where" data-rel="dialog" data-transition="pop">Where</a></li>
</ul>
</div><!-- /content -->
<div data-role="footer" data-id="myfooter" data-position="fixed" data-theme="d">
<div class="controls" data-role="controlgroup" data-type="horizontal">
<a href="#home" data-role="button" data-icon="home">Home</a>
<a href="#search" data-role="button" data-icon="search">Search</a>
<a href="#ask" data-role="button" data-icon="info">Ask</a>
<a href="/index.php" rel="external" data-role="button" data-icon="plus">Full site</a>
</div>
</div><!-- /footer -->
</div><!-- /page -->
<!--
<script type="text/javascript">
$('[data-role=page]').live('pageshow', function (event, ui) {
console.log('pageshow called s');
console.log('pageshow called s2');
try {
_gaq.push( ['_trackPageview', event.target.id] );
console.log('tracked '+event.target.id);
} catch(err) {
console.log('error '+ err);
}
});
</script>-->
<script type="text/javascript">
$(document).delegate('[data-role=page]', 'pageshow', function (event, ui) {
console.log('pageshow event '+ui.prevPage.id);
var url = location.href;
console.log('pageshow url = '+url);
try {
if (location.hash) {
url = location.hash;
console.log('location.hash so now url = '+url);
}
console.log('about to push page '+url);
//_gaq.push(['_trackPageview', url]);
_gaq.push( ['_trackPageview', event.target.id] );
console.log('about to push page '+url);
}
catch(error) {
// error catch
console.log('error '+error);
}
});
</script>
</body>
</html>
最佳答案
GA 代码必须能够向服务器发送请求以跟踪数据。如果您处于离线模式且未发出任何请求，则不会进行跟踪。
关于ios - Google Analytics 如何整合到具有离线/在线模式的 HTML5 移动应用程序中？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16228103/