html - 单击 UIWebView 时如何在 Safari 中打开链接？

Question

当我单击 UIWebview(它就像广告显示)时，我试图在 safari 中打开一个链接。 以下代码正在使用，但发生的情况是当我单击 webview 它在 UIWebview 中打开某些链接(不是全部)时。

- (BOOL)webView:(UIWebView *)webView1 shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType{


    if (webView1==webview) {

        if (UIWebViewNavigationTypeLinkClicked == navigationType) {

            [[UIApplication sharedApplication] openURL:[request URL]];
            return NO;
        }

        return YES;

    }
}

这里发生的情况是，如果该 UIWebView 中有任何文本链接，那么它会正确打开，但是如果 UIWebview 带有图像，那么它会在同一个 UIWebview 而不是新浏览器中打开。

我当前的代码

     - (void)viewDidLoad
    {
        [super viewDidLoad];
        // Do any additional setup after loading the view, typically from a nib.

        [_webView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.example.com/files/ad.htm"]]];
    [_webView setBackgroundColor:[UIColor clearColor]];
    [_webView setOpaque:NO];
    _webView.scrollView.bounces = NO;


    }

-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
    if ( inType == UIWebViewNavigationTypeLinkClicked ) {
        [[UIApplication sharedApplication] openURL:[inRequest URL]];
        return NO;
    }

    return YES;
}

Answer 1

似乎这些图像已使用 anchor 标记链接...

试试这个...

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {

    static NSString *reguler_exp = @"^(([a-zA-Z]|[a-zA-Z][a-zA-Z0-9-]*[a-zA-Z0-9])[.])+([A-Za-z]|[A-Za-z][A-Za-z0-9-]*[A-Za-z0-9])$";
//Regular expression to detect those certain tags..You can play with this regular expression based on your requirement..

    NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", reguler_exp];
//predicate the matched tags.

    if ([resultPredicate evaluateWithObject:request.URL.host]) {
        [[UIApplication sharedApplication] openURL:request.URL];
        return NO; 
    } else {
        return YES; 
    }
}

编辑:不允许第一次调用此委托(delegate)方法。添加一些不会在第一次加载 webview 时调用它的逻辑。

(SOP的新要求，见下方评论)

如何检测uiwebview上的触摸，

1) 将点击手势添加到您的 webview。(在此之前，在您的 viewcontroller.h 中添加 UIGestureRecognizerDelegate)

例子:

UITapGestureRecognizer* singleTap=[[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(handleSingleTap:)];
singleTap.numberOfTouchesRequired=1;
singleTap.delegate=self;
[webview addGestureRecognizer:singleTap];

2)然后添加这个委托(delegate)方法，

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer
{
    //return YES,if you want to control the action natively;
    //return NO,in case your javascript does the rest.
}

注意:如果您想检查触摸是原生的还是 html(javascript)，请查看不错的小教程 here ，关于处理 javascript 事件等......希望这对你有帮助..