php - 如何在没有表格的情况下显示数据库中的产品？

Question

我目前在我的灯数据库中有一个表，我想在其中显示产品。但是我已经展示了产品，但是页面看起来不专业。如何让页面更专业？我不想在表格中显示产品。

我已经在下面发布了我的代码:

<?php
 $con = mysql_connect("localhost","sam","");
 if (!$con)
   {
   die('Could not connect: ' . mysql_error());
   }
mysql_select_db("products", $con);
$result = mysql_query("SELECT * FROM Products_table WHERE catid IN (1,2,7,8)"); 

echo "<table border='1'>
 <tr>
 
 <th>Name</th>
 <th>Image</th>
 <th>Description</th>
 <th>Contact Renter</th>
 <th>Rent price</th>
 </tr>";


while($row = mysql_fetch_array($result))
   {
   echo "<tr>";
   echo "<td>" . $row['productname'] . "</td>";

	
   echo "<td><img src='./images/products/".$row['productimage']."' width='150' height='100' alt=''></td>";
  echo "<td>" . $row['productdescription'] . "</td>";	
   echo "<td>" . $row['rentersdetails'] . "</td>";
   echo "<td>" . $row['rentprice'] . "</td>";
   echo "</tr>";
echo <<<"buttons"
  <td>
     <input class="button_normal" type="button" value="Google Renter" onclick="window.open('https://www.google.co.uk/')"/>; 
     <input class="button_normal" type="button" value="Yahoo" onclick="window.open('https://www.yahoo.co.uk')"/>
  </td>    
buttons;
   }
 echo "</table>";
 mysql_close($con);
 ?>

Answer 1

你可以把结果放在一个变量中:

<?php
 $con = mysql_connect("localhost","sam","");
 if (!$con)
   {
   die('Could not connect: ' . mysql_error());
   }
mysql_select_db("products", $con);
$result = mysql_query("SELECT * FROM Products_table WHERE catid IN (1,2,7,8)"); 

$results = array();
while($row = mysqli_fetch_assoc($query)){
     $results[] = $row;
}

 mysql_close($con);
 ?>

并像这样调用你的 $results 数组:

$results[0]['value']

或者在foreach中

foreach($results as $row => $value) {
    //display your data however you like
}