我有一个 json 数组，看起来像这样:
{
"id": 1,
"children": [
{
"id": 2,
"children": {
"id": 3,
"children": {
"id": 4,
"children": ""
}
}
},
{
"id": 2,
"children": {
"id": 3,
"children": {
"id": 4,
"children": ""
}
}
},
{
"id": 2,
"children": {
"id": 3,
"children": {
"id": 4,
"children": ""
}
}
},
{
"id": 2,
"children": {
"id": 3,
"children": {
"id": 4,
"children": ""
}
}
},
{
"id": 2,
"children": {
"id": 3,
"children": {
"id": 4,
"children": ""
}
}
},
{
"id": 2,
"children": {
"id": 3,
"children": {
"id": 4,
"children": ""
}
}
},
{
"id": 2,
"children": {
"id": 3,
"children": {
"id": 4,
"children": ""
}
}
}]
}
我想要一个函数来删除“ child ”为空的元素。我该怎么做？我不求答案，只求建议
最佳答案
要遍历对象的键，请使用 for .. in 循环:
for (var key in json_obj) {
if (json_obj.hasOwnProperty(key)) {
// do something with `key'
}
}
要测试所有元素的空子元素，您可以使用递归方法:遍历所有元素并递归测试它们的子元素。
可以使用 delete 关键字来删除对象的属性:
var someObj = {
"one": 123,
"two": 345
};
var key = "one";
delete someObj[key];
console.log(someObj); // prints { "two": 345 }
文档:
关于javascript - 从 JSON 对象中删除元素，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/15451290/