我正在尝试根据某些条件将图像加载到 Canvas 中,但仅当我为 drawImage()(drawImage 带有常量注释)函数提供常量作为参数时才会加载图像。我可以添加尽可能多的副本只要我使用常量作为参数,就可以根据需要将图像绘制到 Canvas 上。我的代码有什么问题?请帮忙..
代码如下:
JS:
slotSize=50px;
playArea=9;
var grid=[];
function renderGrid(grid)
{
for(var i=0,y=0;i<playArea;i++,y+=slotSize)
{
for(var j=0,x=0;j<playArea;j++,x+=slotSize)
{
ctx.fillStyle=grid[i][j];
if(grid[i][j]=="white")
{
grass=new Image();
grass.onload=function()
{
//console.log(x+","+y);
ctx.drawImage(grass,x,y,slotSize-2,slotSize-2);
//ctx.drawImage(grass,0,0,slotSize-2,slotSize-2); works!
}
grass.src="../assets/grass.jpg";
}
else
{
ctx.fillRect(x,y,slotSize,slotSize);
}
ctx.strokeRect(x,y,slotSize,slotSize);
}
}
}
window.onload=function loadLocal()
{
canvas=document.getElementById("canvas");
ctx = canvas.getContext("2d");
for(var i=0;i<playArea;i++)
{
grid[i]=[];
}
for(var i=0;i<playArea;i++)
{
for(var i=j;i<playArea;i++)
{
grid[i][j]="white";
}
}
renderGrid();
}
HTML:
<canvas id="canvas" width="450" height="450">
Your browser does not support the canvas element.
最佳答案
http://plnkr.co/edit/h6H3UN45sS6mxtQHlLUz?p=preview
所以基本上你想先了解更多关于变量的上下文和范围的信息。然后您想了解更多有关 Even Listeners 以及如何在异步环境中进行通信的信息。
欢迎提问和评论!
var slotSize=50;
var playArea=9;
var grid=[];
var canvas, ctx;
var grass=new Image();
function renderGrid()
{
for(var i=0,y=0;i<playArea;i++,y+=slotSize)
{
for(var j=0,x=0;j<playArea;j++,x+=slotSize)
{
var value = grid[i][j];
ctx.fillStyle = value;
if(grid[i][j]=="white")
{
console.log(x,y);
ctx.drawImage(grass,x,y,slotSize-2,slotSize-2);
}
else
{
ctx.fillRect(x,y,slotSize,slotSize);
}
ctx.strokeRect(x,y,slotSize,slotSize);
}
}
}
window.onload=function loadLocal()
{
canvas=document.getElementById("canvas");
ctx = canvas.getContext("2d");
for(var i=0;i<playArea;i++)
{
grid[i]=[];
for(var j=i;j<playArea;j++)
{
grid[i][j]="white";
}
}
grass.onload = renderGrid;
grass.src = "http://images.clipartpanda.com/grass-clipart-grass-md.png";
}
关于javascript - js canvas drawImage 不使用循环变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35242252/