javascript - 从 PHP 中的地址形成发件人地址

Question

我这里有这个简单的表单代码

<?php

$EmailFrom = "form@form.com";
$EmailTo = "s@outlook.com";
$Subject = "Form";
$Name = Trim(stripslashes($_POST['Name'])); 
$Budget = Trim(stripslashes($_POST['Budget'])); 
$Email = Trim(stripslashes($_POST['Email'])); 
$Message = Trim(stripslashes($_POST['Message'])); 

// validation
$validationOK=true;
if (!$validationOK) {
  print "<meta http-equiv=\"refresh\" content=\"0;URL=error.htm\">";
  exit;
}

// prepare email body text
$Body = "";
$Body .= "Name: ";
$Body .= $Name;
$Body .= "\n";
$Body .= "Budget: ";
$Body .= $Budget;
$Body .= "\n";
$Body .= "Email: ";
$Body .= $Email;
$Body .= "\n";
$Body .= "Message: ";
$Body .= $Message;
$Body .= "\n";

// send email 
$success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>");

// redirect to success page 
if ($success){
  print "<meta http-equiv=\"refresh\" content=\"0;URL=contactthanks.php\">";
}
else{
  print "<meta http-equiv=\"refresh\" content=\"0;URL=error.htm\">";
}

?>

我想知道如何使顶部的发件人地址与提交的地址相同。

Answer 1

如果我理解正确的话，你可以完全取消这个变量:

$EmailFrom = "form@form.com";

修改后的 mail() 函数应该可以满足您的要求:

// send email 
$success = mail($EmailTo, $Subject, $Body, "From: " . $Email . "\r\n");

请注意，我使用了您已声明的以下变量:

$Email = Trim(stripslashes($_POST['Email']));