我有 html 格式的表单。我从原始 Google 表单复制了操作、输入键和隐藏输入。
<form id="Gform" role="form" action="https://docs.google.com/forms/d/MY-FORM-KEY/formResponse" method="POST" target="_self" onsubmit="">
<input type="text" pattern="^[a-zA-Z][a-zA-ZążźćśęółbńĄŻŹĆŃŚĘÓŁ ]{4,40}$" name="entry.1028663680" value="" id="entry.1028663680" dir="auto" title="What is Your city" class="form-control" placeholder="City" required>
<input type="text" pattern="^[a-zA-Z][a-zA-ZążźćśęółbńĄŻŹĆŃŚĘÓŁ ]{5,40}$" name="entry.1220908348" value="" id="entry.1220908348" dir="auto" title="Your complete name" class="form-control" placeholder="Your name" required>
<input type="tel" name="entry.623688995" value="" id="entry.623688995" dir="auto" title="" class="form-control" placeholder="phone" required>
<input type="email" name="entry.1564973803" value="" id="entry.1564973803" dir="auto" title="" class="form-control" placeholder="email" required>
<input type="hidden" name="entry.383122401" value="WEBSITE" id="entry.383122401" dir="auto" title="" class="form-control" placeholder="E-mail" required>
<input type="hidden" name="draftResponse" value="[,,"-9139933475238999509"]
">
<input type="hidden" name="pageHistory" value="0">
<input type="hidden" name="fbzx" value="-9139933475238999509">
<button type="submit" name="submit" id="sendData" class="btn btn-default">Submit</button>
</form>
我有 te jQuery 脚本,它显示确认:
<script type="text/javascript">
function sendContactForm(){
$("#Gform").fadeOut();
$("#form-container").append('<p class="confirmer">Thanks!<br>Your email was sent.</p>');
};
$('#Gform').submit(function () {
sendContactForm();
return false;
});
</script>
当我删除这个脚本时,表单正在发送,并保存到谷歌,但在点击提交后,我重定向到谷歌“谢谢”页面。我不想重定向并显示确认
就像在脚本中一样。如何解决这个问题?
最佳答案
尝试使用 AJAX 来完成您的任务,当您使用异步函数时,不会重新加载页面,您将在后台发送数据。在数据对象中输入所有输入值,在 done() 和 fail() 函数中定义收到响应时要执行的操作。祝你好运:)
$('#formID').submit(function(e){
e.preventDefault();
$.ajax({
url: "https://docs.google.com/forms/d/1PrgHQALlz0WrvwjhGpLrtIgD5aQ1x-8HrOubkxTLNKs/formResponse",
type: "POST",
data: {
'entry.111': $('#entry_111').val(),
'entry.222': $('#entry_222').val(),
// all data from form
}
}).done(function(data){
yourAction(data);
}).fail(function(data){
failAction(data);
});
});
关于javascript - Google 电子表格网站表单 jQuery 脚本阻止发送,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27509022/