如何在 InstantiateType<T>
中实例化类型 T下面的方法?
我收到错误:'T' 是一个“类型参数”,但像“变量”一样使用。:
(向下滚动查看重构的答案)
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace TestGeneric33
{
class Program
{
static void Main(string[] args)
{
Container container = new Container();
Console.WriteLine(container.InstantiateType<Customer>("Jim", "Smith"));
Console.WriteLine(container.InstantiateType<Employee>("Joe", "Thompson"));
Console.ReadLine();
}
}
public class Container
{
public T InstantiateType<T>(string firstName, string lastName) where T : IPerson
{
T obj = T();
obj.FirstName(firstName);
obj.LastName(lastName);
return obj;
}
}
public interface IPerson
{
string FirstName { get; set; }
string LastName { get; set; }
}
public class Customer : IPerson
{
public string FirstName { get; set; }
public string LastName { get; set; }
public string Company { get; set; }
}
public class Employee : IPerson
{
public string FirstName { get; set; }
public string LastName { get; set; }
public int EmployeeNumber { get; set; }
}
}
修改后的答案:
感谢所有评论,他们让我走上了正确的轨道,这就是我想做的:
using System;
namespace TestGeneric33
{
class Program
{
static void Main(string[] args)
{
Container container = new Container();
Customer customer1 = container.InstantiateType<Customer>("Jim", "Smith");
Employee employee1 = container.InstantiateType<Employee>("Joe", "Thompson");
Console.WriteLine(PersonDisplayer.SimpleDisplay(customer1));
Console.WriteLine(PersonDisplayer.SimpleDisplay(employee1));
Console.ReadLine();
}
}
public class Container
{
public T InstantiateType<T>(string firstName, string lastName) where T : IPerson, new()
{
T obj = new T();
obj.FirstName = firstName;
obj.LastName = lastName;
return obj;
}
}
public interface IPerson
{
string FirstName { get; set; }
string LastName { get; set; }
}
public class PersonDisplayer
{
private IPerson _person;
public PersonDisplayer(IPerson person)
{
_person = person;
}
public string SimpleDisplay()
{
return String.Format("{1}, {0}", _person.FirstName, _person.LastName);
}
public static string SimpleDisplay(IPerson person)
{
PersonDisplayer personDisplayer = new PersonDisplayer(person);
return personDisplayer.SimpleDisplay();
}
}
public class Customer : IPerson
{
public string FirstName { get; set; }
public string LastName { get; set; }
public string Company { get; set; }
}
public class Employee : IPerson
{
public string FirstName { get; set; }
public string LastName { get; set; }
public int EmployeeNumber { get; set; }
}
}
最佳答案
像这样声明你的方法:
public string InstantiateType<T>(string firstName, string lastName)
where T : IPerson, new()
注意最后的附加约束。然后在方法体中创建一个new
实例:
T obj = new T();
关于c# - 在 C# 中,如何在方法中实例化传递的泛型类型?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/658951/