c# - 如何调用base.base.method()？

Question

// Cannot change source code
class Base
{
    public virtual void Say()
    {
        Console.WriteLine("Called from Base.");
    }
}

// Cannot change source code
class Derived : Base
{
    public override void Say()
    {
        Console.WriteLine("Called from Derived.");
        base.Say();
    }
}

class SpecialDerived : Derived
{
    public override void Say()
    {
        Console.WriteLine("Called from Special Derived.");
        base.Say();
    }
}

class Program
{
    static void Main(string[] args)
    {
        SpecialDerived sd = new SpecialDerived();
        sd.Say();
    }
}

结果是:

Called from Special Derived.
Called from Derived. /* this is not expected */
Called from Base.

如何重写 SpecialDerived 类，以便不调用中间类“Derived”的方法？

更新: 我想从 Derived 而不是 Base 继承的原因是 Derived 类包含许多其他实现。由于我不能在这里执行 base.base.method()，我想最好的方法是执行以下操作？

//无法更改源代码

class Derived : Base
{
    public override void Say()
    {
        CustomSay();

        base.Say();
    }

    protected virtual void CustomSay()
    {
        Console.WriteLine("Called from Derived.");
    }
}

class SpecialDerived : Derived
{
    /*
    public override void Say()
    {
        Console.WriteLine("Called from Special Derived.");
        base.Say();
    }
    */

    protected override void CustomSay()
    {
        Console.WriteLine("Called from Special Derived.");
    }
}

Answer 1

只是想在这里添加这个，因为即使经过很多次人们仍然会回到这个问题。当然这是不好的做法，但仍然可以(原则上)做作者想做的事情:

class SpecialDerived : Derived
{
    public override void Say()
    {
        Console.WriteLine("Called from Special Derived.");
        var ptr = typeof(Base).GetMethod("Say").MethodHandle.GetFunctionPointer();            
        var baseSay = (Action)Activator.CreateInstance(typeof(Action), this, ptr);
        baseSay();            
    }
}