我应该有 4 个不同的 slider ,每个 slider 上有 3 个不同的图片。我使用 W3school 的幻灯片 ( https://www.w3schools.com/howto/tryit.asp?filename=tryhow_js_slideshow_multiple ) 来获取前两个(工作正常!)但是当我尝试再添加 2 个时,图片不会显示。
JS:
showSlides(1, 0); <-- this was from W3
showSlides(1, 1); <-- this was from W3
showSlides(1, 2); <-- I added this
showSlides(1, 3); <-- I added this
有人知道如何解决这个问题吗?
这是来自 W3Schools 的:
<div class="slideshow-container">
<div class="grantoppen-slide">
<img src="bilder/grantoppen01.jpg" style="width:100%">
</div>
<div class="grantoppen-slide">
<img src="bilder/grantoppen02.jpg" style="width:100%">
</div>
<div class="grantoppen-slide">
<img src="bilder/grantoppen03.jpg" style="width:100%">
</div>
<a class="prev" onclick="plusSlides(-1, 0)">❮</a>
<a class="next" onclick="plusSlides(1, 0)">❯</a>
</div>
这是我的:
var slideIndex = [1, 1];
var slideId = ["grantoppen-slide", "granbo-slide", "granstua-slide", "granhaug-slide"];
showSlides(1, 0);
showSlides(1, 1);
showSlides(1, 2);
showSlides(1, 3);
function plusSlides(n, no) {
showSlides(slideIndex[no] += n, no);
}
function showSlides(n, no) {
var i;
var bildeSlide = document.getElementsByClassName(slideId[no]);
if (n > bildeSlide.length) {
slideIndex[no] = 1
}
if (n < 1) {
slideIndex[no] = bildeSlide.length
}
for (i = 0; i < bildeSlide.length; i++) {
bildeSlide[i].style.display = "none";
}
bildeSlide[slideIndex[no] - 1].style.display = "block";
}
<p id="hyttenavn-slideshow"><i id="granstua-tekst">Granstua</i></p>
<div class="slideshow-container">
<div class="granstua-slide">
<img src="bilder/granstua01.jpg" style="width:100%">
</div>
<div class="granstua-slide">
<img src="bilder/granstua02.jpg" style="width:100%">
</div>
<div class="granstua-slide">
<img src="bilder/granstua03.jpg" style="width:100%">
</div>
<a class="prev" onclick="plusSlides(-1, 2)">❮</a>
<a class="next" onclick="plusSlides(1, 2)">❯</a>
</div>
最佳答案
编辑:
解决方案 1:正确的方法是实际将 2 个值添加到“slideIndex”:
var slideIndex = [1, 1, 1, 1];
代替:
var slideIndex = [1, 1];
就是这样。这解决了新幻灯片最后一行超出索引的问题。
解决方案 2:如果您计划经常更改幻灯片的数量并使其自动化,您可以在页面加载时使用额外的 initiaaliseSlides()填充每个索引幻灯片的数组强>功能:
var slideIndex = []; // This will be automatically populated
var slideId = ["grantoppen-slide", "granbo-slide", "granstua-slide", "granhaug-slide"];
initialiseSlides();
showSlides(1, 0);
showSlides(1, 1);
showSlides(1, 2); // Note that this is set to 1 now
showSlides(1, 3);
// Initalise all starting slide indexes
function initialiseSlides(){
for (var i = 0; i < slideId.length; i++){
slideIndex[i] = 1;
}
}
function plusSlides(n, no) {
showSlides(slideIndex[no] += n, no);
}
function showSlides(n, no) {
var i;
var x = document.getElementsByClassName(slideId[no]);
if (n > x.length) {slideIndex[no] = 1}
if (n < 1) {slideIndex[no] = x.length}
for (i = 0; i < x.length; i++) {
x[i].style.display = "none";
}
x[slideIndex[no]-1].style.display = "block";
}
解决方案 3: 或者可以像这样修复 showSlides() 以更正自身,而不使用 initialiseSlides()。注意第四行:
function showSlides(n, no) {
var i;
var x = document.getElementsByClassName(slideId[no]);
if (typeof slideIndex[no] === 'undefined') {slideIndex[no] = 1;}
if (n > x.length) {slideIndex[no] = 1}
if (n < 1) {slideIndex[no] = x.length}
for (i = 0; i < x.length; i++) {
x[i].style.display = "none";
}
x[slideIndex[no]-1].style.display = "block";
}
关于javascript - 多个幻灯片不工作(html、css、js),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55558405/