我正在尝试解析从我的 Android 应用中的 URL 获取的 JSON 结果...
我在 Internet 上尝试了一些示例,但无法正常工作。 JSON 数据如下所示:
[
{
"city_id": "1",
"city_name": "Noida"
},
{
"city_id": "2",
"city_name": "Delhi"
},
{
"city_id": "3",
"city_name": "Gaziyabad"
},
{
"city_id": "4",
"city_name": "Gurgaon"
},
{
"city_id": "5",
"city_name": "Gr. Noida"
}
]
获取 URL 并解析 JSON 数据的最简单方法是在 ListView 中显示它
最佳答案
您可以使用 AsyncTask
,您必须进行自定义以满足您的需求,但类似于以下内容
异步任务有三种主要方法:
onPreExecute()
- 最常用于设置和启动进度对话框doInBackground()
- 建立连接并从服务器接收响应(不要尝试将响应值分配给 GUI 元素,这是一个常见错误,无法在后台完成线程)。onPostExecute()
- 这里我们脱离了后台线程,所以我们可以对响应数据进行用户界面操作,或者简单地将响应分配给特定的变量类型。
首先我们将启动类,初始化一个 String
以将结果保存在方法之外但在类内部,然后运行 onPreExecute()
方法设置一个简单的进度对话框。
class MyAsyncTask extends AsyncTask<String, String, Void> {
private ProgressDialog progressDialog = new ProgressDialog(MainActivity.this);
InputStream inputStream = null;
String result = "";
protected void onPreExecute() {
progressDialog.setMessage("Downloading your data...");
progressDialog.show();
progressDialog.setOnCancelListener(new OnCancelListener() {
public void onCancel(DialogInterface arg0) {
MyAsyncTask.this.cancel(true);
}
});
}
然后我们需要设置连接以及我们希望如何处理响应:
@Override
protected Void doInBackground(String... params) {
String url_select = "http://yoururlhere.com";
ArrayList<NameValuePair> param = new ArrayList<NameValuePair>();
try {
// Set up HTTP post
// HttpClient is more then less deprecated. Need to change to URLConnection
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url_select);
httpPost.setEntity(new UrlEncodedFormEntity(param));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
// Read content & Log
inputStream = httpEntity.getContent();
} catch (UnsupportedEncodingException e1) {
Log.e("UnsupportedEncodingException", e1.toString());
e1.printStackTrace();
} catch (ClientProtocolException e2) {
Log.e("ClientProtocolException", e2.toString());
e2.printStackTrace();
} catch (IllegalStateException e3) {
Log.e("IllegalStateException", e3.toString());
e3.printStackTrace();
} catch (IOException e4) {
Log.e("IOException", e4.toString());
e4.printStackTrace();
}
// Convert response to string using String Builder
try {
BufferedReader bReader = new BufferedReader(new InputStreamReader(inputStream, "utf-8"), 8);
StringBuilder sBuilder = new StringBuilder();
String line = null;
while ((line = bReader.readLine()) != null) {
sBuilder.append(line + "\n");
}
inputStream.close();
result = sBuilder.toString();
} catch (Exception e) {
Log.e("StringBuilding & BufferedReader", "Error converting result " + e.toString());
}
} // protected Void doInBackground(String... params)
最后,在这里我们将解析返回,在这个例子中它是一个 JSON 数组,然后关闭对话框:
protected void onPostExecute(Void v) {
//parse JSON data
try {
JSONArray jArray = new JSONArray(result);
for(i=0; i < jArray.length(); i++) {
JSONObject jObject = jArray.getJSONObject(i);
String name = jObject.getString("name");
String tab1_text = jObject.getString("tab1_text");
int active = jObject.getInt("active");
} // End Loop
this.progressDialog.dismiss();
} catch (JSONException e) {
Log.e("JSONException", "Error: " + e.toString());
} // catch (JSONException e)
} // protected void onPostExecute(Void v)
} //class MyAsyncTask extends AsyncTask<String, String, Void>
关于android - 从 Android 上的 URL 简单解析 JSON 并显示在 ListView 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13196234/