我只是想养成像素操作的习惯,它不会改变任何东西。
我使用以下循环来反转每个像素:
var newImage = context.createImageData(canvas.width, canvas.height);
var arr = context.getImageData(0, 0, canvas.width, canvas.height);
var pixels = arr.data;
for(var i = 0; i < pixels.length; i+=4){
var r = 255 - pixels[i];
var g = 255 - pixels[i + 1];
var b = 255 - pixels[i + 2];
var a = pixels[i + 3];
newImage.data[i] = r;
newImage.data[i + 1] = g;
newImage.data[i + 2] = b;
newImage.data[i + 3] = a;
}
但是,当我尝试清除 Canvas 并重写它时,什么也没有发生:
context.clearRect(0, 0, canvas.width, canvas.height);
context.putImageData(newImage, 0, 0);
为什么这不起作用?我做错了什么?
jsfiddle
最佳答案
问题出在图像(尚未加载)上。 你的代码可以工作(观看这个没有图像的 fiddle - http://jsfiddle.net/B82nk/1/ )。
你必须做这样的事情:
var canvas = document.getElementById('canvas');
var context = canvas.getContext('2d');
canvas.width = 500;
canvas.height = 322;
var image_obj = new Image();
image_obj.onload = function(){
var newImage = context.createImageData(canvas.width, canvas.height);
var arr = context.getImageData(0, 0, canvas.width, canvas.height);
var pixels = arr.data;
for(var i = 0; i < pixels.length; i+=4){
var r = 255 - pixels[i];
var g = 255 - pixels[i + 1];
var b = 255 - pixels[i + 2];
var a = pixels[i + 3];
newImage.data[i] = r;
newImage.data[i + 1] = g;
newImage.data[i + 2] = b;
newImage.data[i + 3] = a;
}
context.clearRect(0, 0, canvas.width, canvas.height);
context.putImageData(newImage, 0, 0);
}
image_obj.src = 'http://www.johnchapple.com/jcwp/wp-content/uploads/2012/09/photography_quotes.jpg';
关于javascript - HTML5 Canvas 像素操作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19080529/