我收到错误，找不到页面。 在profile.html中，我写了
<!DOCTYPE html>
<html lang="ja">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>UPLOAD</title>
</head>
<body>
<form action="registration/accounts/fashion_result.html">
<input type="submit" value="ResultShow">
</form>
<div class="container">
<form action="{% url 'accounts:upload_save' %}" method="POST" enctype="multipart/form-data">
{% csrf_token %}
<input type="file" name="files[]" multiple>
<input type="hidden" value="{{ p_id }}" name="p_id">
<input type="submit" value="Upload">
</form>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
</body>
</html>
在这一部分
<form action="registration/accounts/fashion_result.html">
<input type="submit" value="ResultShow">
</form>
我想要进行屏幕转换(如果我放置此按钮，我想在浏览器中看到 Fashion_result.html。
但是现在，我收到了错误。 我该如何解决这个问题？
此外，我添加到 urls.py
from django.conf.urls import patterns, url
from django.views.generic import TemplateView
urlpatterns = patterns('',
url(r'^/fashionresults/$', TemplateView.as_view(template_name='registration/accounts/fashion_result.html'), name='fashionresults'
)
在 profile.html 中
<form action="registration/accounts/fashion_result.html">ResultShow</form>
(目录下有fashion_result.html)
最佳答案
用户TemplateView解决此问题
from django.conf.urls import patterns, url
from django.views.generic import TemplateView
urlpatterns = patterns('',
url(r'^/test/$', TemplateView.as_view(template_name='todo/index.html'), name="test"),
)
在 html 页面中
<a href="{% url 'test' %}" >ResultShow</a>
关于python - 找不到页面错误。请求地址是否错误？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/42241958/