在将我的问题指定为重复问题之前,请完整阅读我的问题。 您好,我尝试在按键期间动态验证密码。实际上它在输入密码时对我有用。但是当我删除密码时,只有 2 个条件满足。我的代码和图片如下:
我的密码框html代码是
<div class="form-group has-feedback">
<input class="form-control" id="NewPassword" placeholder="New Password" onkeypress="EnterPassword()" onkeydown="DeletePassword()" type="password">
<span class="glyphicon glyphicon-lock form-control-feedback"></span>
</div>
我在密码的每个条件前面使用了 glyphicon-remove。当我输入密码时,如果条件满足,每个图标都会变为 glyphicon-ok。
假设我的密码是Password@123,它包含了我所有需要的东西,所以所有的图标都变成了ok。
下面函数的代码:
<script type="text/javascript" >
function EnterPassword() {
$("#NewPassword").keyup(function () {
var regex1 = new Array();
var regex2 = new Array();
var regex3 = new Array();
var regex4 = new Array();
regex1.push("[A-Z]"); //Uppercase Alphabet.
regex2.push("[a-z]"); //Lowercase Alphabet.
regex3.push("[0-9]"); //Digit.
regex4.push("[!@@#$%^&*]"); //Special Character.
if ($(this).val().length>6) {
$("#Length").removeClass("glyphicon glyphicon-remove").addClass("glyphicon glyphicon-ok");
}
for (var i = 0; i < regex1.length; i++) {
if (new RegExp(regex1[i]).test($(this).val())) {
$("#UpperCase").removeClass("glyphicon glyphicon-remove").addClass("glyphicon glyphicon-ok");
}
}
for (var i = 0; i < regex2.length; i++) {
if (new RegExp(regex2[i]).test($(this).val())) {
$("#LowerCase").removeClass("glyphicon glyphicon-remove").addClass("glyphicon glyphicon-ok");
}
}
for (var i = 0; i < regex3.length; i++) {
if (new RegExp(regex3[i]).test($(this).val())) {
$("#Numbers").removeClass("glyphicon glyphicon-remove").addClass("glyphicon glyphicon-ok");
}
}
for (var i = 0; i < regex4.length; i++) {
if (new RegExp(regex4[i]).test($(this).val())) {
$("#Symbols").removeClass("glyphicon glyphicon-remove").addClass("glyphicon glyphicon-ok");
}
}
});
}
function DeletePassword() {
$("#NewPassword").keyup(function () {
var regex1 = new Array();
var regex2 = new Array();
var regex3 = new Array();
var regex4 = new Array();
regex1.push("[A-Z]"); //Uppercase Alphabet.
regex2.push("[a-z]"); //Lowercase Alphabet.
regex3.push("[0-9]"); //Digit.
regex4.push("[!@@#$%^&*]"); //Special Character.
var thisVal =$(this).val();
if ($(this).val().length<6) {
$("#Length").removeClass("glyphicon glyphicon-ok").addClass("glyphicon glyphicon-remove");
}
for (var i = 0; i < regex1.length; i++) {
if (new RegExp(regex1[i]).test(!thisVal)) {
$("#UpperCase").removeClass("glyphicon glyphicon-ok").addClass("glyphicon glyphicon-remove");
}
}
for (var i = 0; i < regex2.length; i++) {
if (new RegExp(regex2[i]).test(!thisVal)) {
$("#LowerCase").removeClass("glyphicon glyphicon-ok").addClass("glyphicon glyphicon-remove");
}
}
for (var i = 0; i < regex3.length; i++) {
if (new RegExp(regex3[i]).test(!thisVal)) {
$("#Numbers").removeClass("glyphicon glyphicon-ok").addClass("glyphicon glyphicon-remove");
}
}
for (var i = 0; i < regex4.length; i++) {
if (new RegExp(regex4[i]).test(!thisVal)) {
$("#Symbols").removeClass("glyphicon glyphicon-ok").addClass("glyphicon glyphicon-remove");
}
}
});
}
</script>
注意:UpperCase、LowerCase、Numbers、Symbols 是我为使用字形删除图标的标签提供的 ID 名称。 如果我的代码不能完全工作意味着我的问题可能会重复。但它部分工作,所以如果我的代码有任何错误,请告诉我。
提前致谢
最佳答案
我们可以大大简化您的代码。
首先,我们将使用 jQuery 的 .on
来绑定(bind)事件,而不是使用内联事件处理程序。
接下来,我们会将您的规则整合到一个包含规则目标的 JSON 对象数组中。
然后我们根据需要迭代基于 Regex 的规则添加和删除类
/*Actual validation function*/
function ValidatePassword() {
/*Array of rules and the information target*/
var rules = [{
Pattern: "[A-Z]",
Target: "UpperCase"
},
{
Pattern: "[a-z]",
Target: "LowerCase"
},
{
Pattern: "[0-9]",
Target: "Numbers"
},
{
Pattern: "[!@@#$%^&*]",
Target: "Symbols"
}
];
//Just grab the password once
var password = $(this).val();
/*Length Check, add and remove class could be chained*/
/*I've left them seperate here so you can see what is going on */
/*Note the Ternary operators ? : to select the classes*/
$("#Length").removeClass(password.length > 6 ? "glyphicon-remove" : "glyphicon-ok");
$("#Length").addClass(password.length > 6 ? "glyphicon-ok" : "glyphicon-remove");
/*Iterate our remaining rules. The logic is the same as for Length*/
for (var i = 0; i < rules.length; i++) {
$("#" + rules[i].Target).removeClass(new RegExp(rules[i].Pattern).test(password) ? "glyphicon-remove" : "glyphicon-ok");
$("#" + rules[i].Target).addClass(new RegExp(rules[i].Pattern).test(password) ? "glyphicon-ok" : "glyphicon-remove");
}
}
/*Bind our event to key up for the field. It doesn't matter if it's delete or not*/
$(document).ready(function() {
$("#NewPassword").on('keyup', ValidatePassword)
});
.glyphicon-remove {
color: red;
}
.glyphicon-ok {
color: green;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="form-group has-feedback">
<input class="form-control" id="NewPassword" placeholder="New Password" type="password">
<span class="glyphicon glyphicon-lock form-control-feedback"></span>
</div>
<div id="Length" class="glyphicon glyphicon-remove">Must be at least 7 charcters</div>
<div id="UpperCase" class="glyphicon glyphicon-remove">Must have atleast 1 upper case character</div>
<div id="LowerCase" class="glyphicon glyphicon-remove">Must have atleast 1 lower case character</div>
<div id="Numbers" class="glyphicon glyphicon-remove">Must have atleast 1 numeric character</div>
<div id="Symbols" class="glyphicon glyphicon-remove">Must have atleast 1 special character</div>
关于javascript - 如何使用 jquery/javascript 动态检查密码验证?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52069794/