请告诉我我的代码出了什么问题!!!!
新支付.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Process New Payment</title>
</head>
<body>
<h1>Please Input Payment Details</h1>
<fieldset>
<legend>New Payment</legend>
<form action="process-payment.php" method="post" />
<table>
<tr>
<td>Date:</td><td><input type="date" name="date" /><br /></td>
</tr>
<tr>
<td>Today's Charge:</td><td><input type="text" name="charge" /><br /></td>
</tr>
<tr>
<td>Today's Payment:</td><td><input type="text" name="payment" /><br /></td>
</tr>
<tr>
<td>Client Number:</td><td><input type="text" name="client_no" /><br /></td>
</tr>
<tr>
<td>Client Name:</td><td><input type="text" name="client_name" /><br /></td>
</tr>
<tr>
<td>Check Number:</td><td><input type="text" name="check_no" /><br /></td>
</tr>
<tr>
<td>Check Amount:</td><td><input type="text" name="check" /><br /></td>
</tr>
<tr>
<td>Cash Amount:</td><td><input type="text" name="cash" /><br /></td>
</tr>
<tr>
<td>Notes:</td><td><input type="text" name="notes" /><br /></td>
</tr>
<tr>
<td>Staff Initials:</td><td><input type="text" name="staff_initials" /><br /></td>
</tr>
</table>
<input type="submit" value="Process Payment">
</form>
</fieldset>
<br />
</body>
</html>
流程支付.php
<?php
define('DB_NAME', 'DBNAME');
define('DB_USER', 'USERNAME');
define('DB_PASS', '');
define('DB_HOST', 'localhost');
$link = mysql_connect(DB_HOST, DB_USER, DB_PASS);
if (!$link) {
dir('There was a problem when trying to connect to the host. Please contact Tech Support. Error: ' . mysql_error());
}
$db_selected = mysql_select_db(DB_NAME, $link);
if (!$link) {
dir('There was a problem when trying to connect to the database. Please contact Tech Support. Error: ' . mysql_error());
}
$date = $_POST['date'];
$charge = $_POST['charge'];
$payment = $_POST['payment'];
$client_no = $_POST['client_no'];
$client_name = $_POST['client_name'];
$check_no = $_POST['check_no'];
$check = $_POST['check'];
$cash = $_POST['cash'];
$notes = $_POST['notes'];
$staff_initials = $_POST['staff_initials'];
$sql = "INSERT INTO payments (date, charge, payment, client_no, client_name, check_no, check, cash, notes, staff_initials) VALUES ('$date', '$charge', '$payment', '$client_no', '$client_name', '$check_no', '$check', '$cash', '$notes', '$staff_initials')";
if (!mysql_query($sql)) {
die('Error: ' . mysql_error());
}
?>
我不知道出了什么问题，但当我按“处理付款”时出现错误:
Error: You have an error in your SQL syntax; check the manual that corresponds to your >MySQL server version for the right syntax to use near 'check, cash, notes, staff_initials) >VALUES ('2012-09-24', '$0.00', '$20.00', '46' at line 1
最佳答案
CHECK 是 MySQL reserved keyword 。您必须将其括在反引号中才能将其用作列或表标识符。
$sql = "INSERT INTO payments (date, charge, payment, client_no, client_name, check_no, `check`, cash, notes, staff_initials) VALUES ('$date', '$charge', '$payment', '$client_no', '$client_name', '$check_no', '$check', '$cash', '$notes', '$staff_initials')";
请注意，您的脚本容易受到 SQL 注入(inject)攻击。至少，您必须对每个输入变量调用 mysql_real_escape_string()。
// As in:
$charge = mysql_real_escape_string($_POST['charge']);
关于php - 如何将 HTML 表单中的数据插入 MySQL，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12593350/