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)1
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)
我从一个更大的数组中切出以下内容。现在我想遍历这个数组并过滤一些值。我使用带有 true 选项的 sliced_array 功能来保留 [2] 数组编号。
现在这个数组有几个子数组，我需要一些值和一些过滤。在最终结果中，我想创建一个列出数组编号(1 到 12)的表，并在它后面有链接。 (所以一个 2 列表)我不需要的是剧集编号的第二个数组。这始终是剧集中的 [1] 数组。这是“俄语”部分，我在最终结果中不需要它。
我如何遍历它并得到一个简单的 html 表格作为输出？我一直在尝试使用 foreach() 方法，但现在我得到的只是“Array”。
编辑 答案确实是做多个foreach。
<?php
$json = file_get_contents("http://trendico.ru/api/moviebox/get_tv_data?id=1&season=7");
$array = json_decode($json, TRUE);
//Create an index array
$indexarray = (array_values($array));
//Create an array with only the episodes
$episodes = array_slice($indexarray, 2, 1);
foreach($array as $arrayl1) {
foreach($arrayl1 as $arrayl2) {
foreach($arrayl2 as $arrayl3) {
foreach($arrayl3 as $key => $val) {
echo "$key=>$val"."<br>";
}
}
}
}
?>
最佳答案
使用递归函数和is_array。
function doSomething(&$complex_array){
foreach ($complex_array as $n => $v)
{
if (is_array($v))
doSomething($v);
else
do whatever you want to do with a single node
}}
关于php - 遍历索引数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16102323/