linux - linux 中的 monitor-cpu 脚本

Question

 1  # this script checks average cpu load for last 5 minutes
 2  # since this server has only one core the system will be fully #utilized when average cpu load values reach 1.00.
 3  # This script will send warning alert if value exceedes 0.80 so that action can be taken promptly.
 4  # finally it will display the top 10 users and their processes #with highest cpu utilization.
 5  #!/bin/bash
 6  up=$(uptime | awk '{ print$10 }'| sed 's/,$//')
 7  if($up -gt 0.80];
 8  echo "============================================" >> /tmp/load
 9  ps -eo pcpu,pid,user,args | sort -k 1 -r | head -10 >> /tmp/load
10  mail -s "warning alert on QA server , CPU load exceedes the warning threshold" priyank.dewli@qpay.com.qa issuing-alerts@nexxuspg.com < /tmp/load
11  exit

=======================
 error after executing the script
line 12: syntax error: unexpected end of file

Answer 1

检查这一行:

if($up -gt 0.80];

我觉得你想要

if (( $(bc <<< "$up > 0.8") ))
then
    echo ...
    ps ...
    mail ...
fi