我正在编写一个程序,以编程方式与 SPIN 模型检查器的交互模块进行通信。为此,我需要重定向 SPIN 的 I/O,从我的程序中启动它,然后重复读取和写入它。为了进行测试,我使用以下只有一个输入和一个输出的短程序而不是自旋:
#include <string>
#include <iostream>
using std::cin;
using std::cout;
using std::string;
void sprint(string s);
int main()
{
std::string s = "empty";
cin >> s;
cout << "\n\tthe text is: " << s;
return 0;
}
我的程序,主要取自this answer , 是:
#include <stdio.h>
#include <stdlib.h>
#include <string>
#include <cstring>
#include <unistd.h>
#include <errno.h>
#include <iostream>
#define PIPE_READ 0
#define PIPE_WRITE 1
#define maxReadSize 2048
using std::cout;
using std::cin;
using std::string;
int createChild(const char* szCommand, const char* aArguments, const char* szMessage);
int main()
{
createChild("./inout" , "inout", "hello");
return 0;
}
int createChild(const char* szCommand, const char* aArguments, const char* szMessage)
{
int cStdinPipe[2];
int cStdoutPipe[2];
int nChild;
char nChar;
int nResult;
if (pipe(cStdinPipe) < 0)
{
return -1;
}
if (pipe(cStdoutPipe) < 0)
{
close(cStdinPipe[PIPE_READ]);
close(cStdinPipe[PIPE_WRITE]);
return -1;
}
nChild = fork();
if (0 == nChild)
{
// child continues here
cout.flush();
close(cStdinPipe[PIPE_WRITE]);
// redirect stdin
if (dup2(cStdinPipe[PIPE_READ], STDIN_FILENO) == -1)
{
exit(errno);
}
// redirect stdout
if (dup2(cStdoutPipe[PIPE_WRITE], STDOUT_FILENO) == -1)
{
exit(errno);
}
// all these are for use by parent only
close(cStdinPipe[PIPE_READ]);
close(cStdoutPipe[PIPE_READ]);
close(cStdoutPipe[PIPE_WRITE]);
// run child process image
nResult = execlp(szCommand, aArguments, NULL);
// if we get here at all, an error occurred, but we are in the child
// process, so just exit
exit(nResult);
}
else if (nChild > 0)
{
// parent continues here
string messageFromChild = "";
string messageFromParent = "";
char readBuffer[maxReadSize];
int bytesWritten = 0;
int bytesRead = 0;
// close unused file descriptors, these are for child only
close(cStdinPipe[PIPE_READ]);
close(cStdoutPipe[PIPE_WRITE]);
// write to child
if (NULL != szMessage)
{
bytesWritten = write(cStdinPipe[PIPE_WRITE], szMessage, strlen(szMessage));
}
// read from child
bytesRead = read(cStdoutPipe[PIPE_READ], readBuffer, maxReadSize);
cout << "\nChild says: " << readBuffer << "\n";
// done with these in this example program, you would normally keep these
// open of course as long as you want to talk to the child
close(cStdinPipe[PIPE_WRITE]);
close(cStdoutPipe[PIPE_READ]);
std::cout << "\n\nParent ending";
}
else
{
// failed to create child
close(cStdinPipe[PIPE_READ]);
close(cStdinPipe[PIPE_WRITE]);
close(cStdoutPipe[PIPE_READ]);
close(cStdoutPipe[PIPE_WRITE]);
}
return nChild;
}
运行此程序会导致死锁,子进程卡在 cin
上,而父进程卡在 read()
上。删除这些调用中的任何一个都会导致两个程序运行到终止并正常退出。 write()
和 cout
都可以正常工作。
最佳答案
问题出在 read()
和 write()
如何在各种流/文件/管道上工作。我的 write()
无法与它已完成写入的 read()
通信。 Read()
依赖于 EOF
,它仅在管道的写入端关闭后才发送。当然,一旦它关闭,它就永远消失了,我无法重新打开它来发送另一条消息。
因此,我切换到命名管道 (fifo
),这样我就可以在每次写入后重新打开管道。
关于c++ - 与具有重定向 I/O 的子进程通信时出现死锁,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51010038/