linux - 调用未安装的例程时 Shell 脚本不会失败

Question

我有一个用于安装 Jenkins 插件的简单 shell 脚本:

installPlugin() {
    {...}
}

  for f in ${plugin_dir}/*.hpi ; do
    #without optionals
    deps=$( unzip -p ${f} META-INF/MANIFEST.MF | tr -d '\r' | sed -e ':a;N;$!ba;s/\n //g' | grep -e "^Plugin-Dependencies: " | awk '{ print $2 }' | tr ',' '\n' | grep -v "resolution:=optional" | tr '\n' ' ' )
    for plugin in $deps; do
      installPlugin "$plugin" 1 && changed=1
    done
  done

我像这样从 Dockerfile 调用这个脚本:

RUN JENKINS_HOME=$JENKINS_HOME \
    http_proxy=$http_proxy \
    https_proxy=$https_proxy \
    $JENKINS_HOME/install_plugin.sh \
    ace-editor:1.1 \

即使 unzip 例程未安装在 Dockerfile 中，当我运行 docker build 时，即使缺少 unzip，输出仍然是成功的。如果以下步骤失败，我希望构建失败:

deps=$( unzip -p ${f} META-INF/MANIFEST.MF | tr -d '\r' | sed -e ':a;N;$!ba;s/\n //g' | grep -e "^Plugin-Dependencies: " | awk '{ print $2 }' | tr ',' '\n' | grep -v "resolution:=optional" | tr '\n' ' ' )

非常感谢任何帮助!

乐

脚本输出如下:

/var/jenkins/install_plugin.sh: line 62: unzip: command not found

 deps=

但是，即使该脚本失败，docker build 也不会失败:

Successfully built 54f5a5ec567d

Answer 1

我最后做了这样一张空支票:

 for f in ${plugin_dir}/*.hpi ; do

    manifestMf=$(unzip -p ${f} META-INF/MANIFEST.MF | tr -d '\r')
    if [ $manifestMf=="" ]; then
        echo "Invalid META-INF/MANIFEST inside $f"
        exit 1
    fi;

    #without optionals
    deps=$(echo $manifestMf | sed -e ':a;N;$!ba;s/\n //g' | grep -e "^Plugin-Dependencies: " | awk '{ print $2 }' | tr ',' '\n' | grep -v "resolution:=optional" | tr '\n' ' ' )
    # with optionals
    #deps=$( unzip -p ${f} META-INF/MANIFEST.MF | tr -d '\r' | sed -e ':a;N;$!ba;s/\n //g' | grep -e "^Plugin-Dependencies: " | awk '{ print $2 }' | tr ',' '\n' | tr '\n' ' ' )
    for plugin in $deps; do
      installPlugin "$plugin" 1 && changed=1
    done
  done
done