我正在尝试将 unix 命令的输出覆盖到文件，但它一直将输出附加到文件。
wget --progress=dot http://test.com/example.zip 2>&1 | grep --line-buffered "%" | \
sed -u -e "s,\.,,g" | awk '{printf(" %4s", $2)}' > log.txt
可在此处找到引用资料:Tutorial
这是我得到的输出 - log.txt
0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 0% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 1% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 2% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3% 3%
应该只有百分之一
10%
我哪里做错了？
最佳答案
使用三种工具(grep、sed 和awk)来实现其中任何一种工具的功能，这表明编写原始脚本并不真正理解这些工具中的任何一个。
仅使用 awk(并且仅使用 posix awk 功能，afaik):
wget --progress=dot http://test.com/example.zip 2>&1 |
awk 'match($0,/[0-9]{1,3}%/){printf "%4s",substr($0,RSTART,RLENGTH) >"log.txt";
close("log.txt")}'
(我刚刚用 gawk、mawk 和 original-awk(在 Mac OS X 上使用)检查了这个，最后一个似乎不理解大括号重复运算符，所以你需要编写 match($0,/[0-9]?[0-9]?[0-9]%/)。使用 gawk，有一些可能的简化。)
这是一个仅使用 grep 的简单解决方案，尽管它的行为几乎与您的原始行为完全相同(即，它不会在每一行上倒回文件。我们会谈到这一点。)
wget --progress=dot http://test.com/example.zip 2>&1 |
grep --line-buffered -oE '[0-9]{1,3}%'
有多种方法可以覆盖每一行的文件；这是一个简单的:
for PCT in $(wget --progress=dot http://test.com/example.zip 2>&1 |
grep --line-buffered -oE '[0-9]{1,3}%'); do
printf '%4s\n' $PCT > log.txt
done
关于linux - 无法覆盖到文件，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/19936209/