linux - 捕获错误并要求在 BASH 中手动输入

Question

我有以下代码:

if [ -e /etc/my.cnf ]; then
    _out_fn="/etc/my.cnf"
        if [ ! -e ${_out_fn}_orig ] ; then
        cp $_out_fn ${_out_fn}_orig
        fi
    cp /dev/null $_out_fn
    while read line ; do
    set -- $line
        if [ "$1" = "[mysqld]" ] ; then
            echo $line >> $_out_fn
            line="safe-show-database
            skip-networking
            local-infile=0
            symbolic-links=0"
        fi
    echo $line >> $_out_fn
    done < ${_out_fn}_orig
    echo "$MySQL Securing Complete! "
else
    echo "$MySQL Configuration File Not Found! "
fi

有没有办法让代码选择在失败时请求手动位置？

Answer 1

使用读取。要求手动输入的代码片段可能如下所示:

config_location=
while : ; do
        echo -n "Enter the path to the configuration file: "
        read config_location
        if test -r "$config_location"; then
                break
        fi
        echo "File $config_location not found or is unreadable, let's try again."
done
echo "OK, $config_location exists."

这里我们继续询问用户，直到他提供的路径存在并且可读(test -r)。 while : ; do 是一个无限循环。如果你只需要询问一次路径，你只需要这样:

echo -n "Enter the path to the configuration file: "
read config_location