我有一个 bash 脚本,它有大约 2000 行代码,在这个脚本的不同行中,脚本将一些状态消息写入日志文件,即 LogFiles.txt、bills.txt 我只想评论(搜索并替换文本)所有在 LogFiles.txt 中写入状态消息的行
示例脚本文件:
echo "+++++++++++++++++++++">>bills.txt
echo "doing some stuff">>bills.txt
echo "starting
to execute some commands">>LogFiles.txt
echo "----------------------">>LogFiles.txt
ls
cat someFile.txt| grep "search me"
echo "search results found">>LogFiles.txt
echo "----------------------">>LogFiles.txt
echo "+++++++++++++++++++++">>bills.txt
echo "doing some more stuff">>bills.txt
some other commands...
echo "finshing
script
execution">>LogFiles.txt
echo "----------------------">>LogFiles.txt
期望的输出:
echo "+++++++++++++++++++++">>bills.txt
echo "doing some stuff">>bills.txt
/*echo "starting
to execute some commands">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
ls
cat someFile.txt| grep "search me"
/*echo "search results found">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
echo "+++++++++++++++++++++">>bills.txt
echo "doing some more stuff">>bills.txt
some other commands...
/*echo "finshing
script
execution">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
到目前为止,我已经使用了以下命令,但结果并不好:
sed -e 's/echo/\/\*echo/gI' -e 's/LogFiles.txt/LogFiles.txt\*\//gI' samplescript.sh
此命令产生的结果:
/*echo "doing some stuff">>bills.txt
/*echo "starting
to execute some commands">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
ls
cat someFile.txt| grep "search me"
/*echo "search results found">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
some other commands...
/*echo "finshing
script
execution">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
当 sed -e 命令的第一部分将所有 echo 替换为/*echo 时,问题就出现了,这是一种错误的方法,因为我不需要为 bills.txt 注释 echo。
最佳答案
在 bash 中使用 : '
和 '
语法进行多行注释,正如@Aserre 所指出的那样,使用 sed:
sed -r -e "/^echo/ {/>>/ bb; :a; N; />>/! ba; :b; />>LogFiles\.txt/I {s/^echo/: ' echo/; s/(>>.*)$/\1 '/}}" samplescript.sh
也可以使用-i
直接写入脚本文件。
sed命令解释:
/^echo/ { # in a line that starts with 'echo'
/>>/ bb # if also already contains '>>' jump forward to 'b' label
:a # 'a' label to jump to
N # read next line and add it to pattern space
/>>/! ba # if pattern space not contains '>>' jump back to 'a' label
:b # 'b' label to jump to
/>>LogFiles\.txt/I { # now if pattern space contains '>>LogFiles.txt' case insensitive
s/^echo/: ' echo/ # add open comment before 'echo'
s/(>>.*)$/\1 '/ # add close comment at the end of the line with '>>'
}
}
关于linux - 在字符串中找到模式后评论 bash 行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50580936/