regex - 基于空行的新文本文件

Question

我有一个如下所示的文本文件:

6789 Here is a bunch of text

4565 More text......................................................
.....etc

我需要提取第一个单词(数字)并创建一个包含以下所有文本的新文件，将第一个单词作为文件名直到一个空行，然后重复创建许多文本文件。

Answer 1

awk 行可以做到:

awk 'BEGIN{RS=""} {fn=$1;gsub(/^[0-9]+\s/,"");print $0 > (fn".txt")}' yourFile

测试:

kent$  l 
total 0
(no file in current dir)

kent$  echo "6789 Here is a bunch of text

4565 More text......................................................
.....etc"|awk 'BEGIN{RS=""} {fn=$1;gsub(/^[0-9]+\s/,"");print $0 > (fn".txt")}'

kent$  ls
4565.txt  6789.txt

and, the contents are:

kent$  head *.txt
==> 4565.txt <==
More text......................................................
.....etc

==> 6789.txt <==
Here is a bunch of text