我试图找出通过我的系统发送文件需要多长时间:我将时间戳记录在两个日志文件中,如下所示:
首先
4824597 1371853829 /home/customer1/ITAM.xml
.
.
.
.
4824597 1371854003 /home/customer46/ITAM.xml
第二个
4824597 1371854003 /home/customer1/ITAM.xml
.
.
.
.
4824597 1371854003 /home/customer46/ITAM.xml
下面是我用来减去时间戳的命令。
awk '{
sub(/:/," ",$2);
t1=mktime(strftime("%Y %m %d")" "$2" 00");
getline < "/root/ITAM.txt";
sub(/:/," ",$2);
t2=mktime(strftime("%Y %m %d")" "$2" 00");
print $3": "t2-t1" s"
}' /root/fileSizelog.txt
我现在遇到的问题是我得到了奇怪的输出,比如 -7185759 s。它似乎正在与 EPOCH 时间进行区分。有人可以帮忙吗?
最佳答案
您在问题中提到有两个日志文件,尽管您只发布了一个。因此,我将以您的输入数据为例,展示您如何找到解决方案。
根据新的示例数据更新了解决方案。
使用的示例数据:
$ cat first
824597 1371853829 /home/customer1/ITAM.xml
4824597 1371854003 /home/customer46/ITAM.xml
$ cat second
4824597 1371854003 /home/customer1/ITAM.xml
4824597 1371854003 /home/customer46/ITAM.xml
我添加了注释以使其更容易理解。
script.awk 的内容:
# This syntax in combination with next (seen below) allows us to work on the first file
# entirely
NF==FNR {
# we are indexing the filename and assign it start time value
start[$3]=$2
# next allows us to skip the rest action statements
next
}
# once the first log file is looped over we store the second log file in end array
{
end[$3]=$2
}
# End block is where we are doing most of our computation since we have scanned
# through the two files and now are ready to calculate the difference
END {
# we iterate over the start array and pick an index value (that is a file)
for (filestart in start) {
# we do the same for our second array
for (fileend in end) {
# if the filename are same then we are ready to do the difference
if (filestart == fileend) {
# we subtract start time from end time
diff = end[fileend] - start[filestart];
# we use sprintf function to avoid printing the difference so that we can store it in a variable
diff = sprintf("%dh:%dm:%ds",diff/(60*60),diff%(60*60)/60,diff%60)
# we print the filename and the time lag
print filestart,diff
# we delete the filename indices to reduce the size of array for performance reasons
delete start[filestart]
delete end[fileend]
}
}
}
}
将脚本作为 awk -f script.awk log.file
运行或作为:
$ awk '
NR==FNR {
start[$3]=$2
next
}
{
end[$3]=$2
}
END {
for(filestart in start) {
for(fileend in end) {
if (filestart == fileend) {
diff = end[fileend] - start[filestart];
diff = sprintf("%dh:%dm:%ds",diff/(60*60),diff%(60*60)/60,diff%60)
print filestart,diff
delete start[filestart]
delete end[fileend]
}
}
}
}' first second
/home/customer46/ITAM.xml 0h:0m:0s
/home/customer1/ITAM.xml 0h:2m:54s
关于linux - 如何减去 2 个日志文件中两个时间戳的差异,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17245135/